For a particle executing simple harmonic motion, the kinetic energy is given by K=K0cos2ωt. The maximum value of potential energy for the given particle: 
1.  maybe K0
2.  must be K0
3.  maybe more than K0
4. both (1) and (3)

Subtopic:  Energy of SHM |
 55%
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A body of mass M is situated in a potential field. The potential energy of the body is given by Ux = U01 - cos Kx; where x is position, K and U0 are constant. Period of small oscillations of the body will be:

1.  2πMU0K2

2.  2πMU0K2

3.  2πU0K2M

4.  2πU0MK2

Subtopic:  Energy of SHM |
 75%
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A particle is executing SHM about origin along X-axis, between points A(α, 0) and B(-α, 0). Its time period of oscillation is T. The magnitude of its acceleration T12 second after the particle reaches point A will be

1.  23πTα

2.  22π2T2α

3.  23π2T2α

4.  3π2T2α

Subtopic:  Simple Harmonic Motion |
 70%
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A particle executes linear oscillation such that its epoch is zero. The ratio of the magnitude of its displacement in 1st second and 2nd second is (Time period = 12 seconds)

1.  13 + 1

2.  13 - 1

3.  3 - 12

4.  33 - 1

Subtopic:  Simple Harmonic Motion |
 70%
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A block of mass 0.02 kg is connected with spring and is free to oscillate on a horizontal smooth surface as shown. The angular frequency of oscillation is 2 rad s-1. The block is pulled by 4 cm (from equilibrium position) and then pushed towards the spring with a velocity of 8 cm/s. The amplitude of oscillation is (Neglect any damping)

                    

1.  32 cm

2.  42 cm

3.  22 cm

4.  1 cm

Subtopic:  Combination of Springs |
 78%
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A particle moves on a circular path with uniform speed about the origin. The (xt) graph will be:
(x: value of xcoordinate; ttime)

1. 2.
3. 4.
Subtopic:  Types of Motion |
 67%
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A simple pendulum has time period T. The bob is given negative charge and surface below it is given a positive charge. The new time period will be:
1. less than T
2. greater than T
3. equal to T
4. infinite

Subtopic:  Angular SHM |
 56%
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A simple pendulum attached to the ceiling of a stationary lift has a time period of 1 s. The distance y covered by the lift moving downward varies with time as y = 3.75 t2, where y is in meters and t is in seconds. If g = 10 m/s2, then the time period of the pendulum will be:

1. 4 s 2. 6 s
3. 2 s 4. 12 s
Subtopic:  Types of Motion | Simple Harmonic Motion | Angular SHM |
 62%
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Which of the following may represent the potential energy of a body in SHM?
(symbols have their usual meaning)

(A) mω2A2
(B) 12mω2A2
(C) 2A2+1mω2

Choose the correct option from the options given below:
1. (A) and (B) only
2. (B) only
3. (B) and (C) only
4. (A), (B) and (C) 
Subtopic:  Energy of SHM |
 73%
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A particle moves according x = 6 cm cosπ2tAverage velocity of the particle in the time interval between t = 0 to t = 3 s is

1.  1 cm/s

2.  3.5 cm/s

3.  2 cm/s

4.  6 cm/s

Subtopic:  Types of Motion | Simple Harmonic Motion | Angular SHM |
 58%
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