Metals have conductivity of the order of (ohm^-1 m^-1):-

1. 10¹²

2. 10⁸

3. 10²

4. 10^-6

An electrochemical cell is shown below Pt, H₂(1 atm)| HCI (0.1 M)CH₃COOH (0.1 M)|

H₂(1 atm), Pt The EMF of the cell will not be zero, because

1. EMF depends on molarities of acids used

2. pH of 0.1 M HCl and 0.1 M CH₃COOH is not same

3. the temperature is constant

4. acids used in two compartments are different

Saturated solution of KNO₃ is used to make 'salt-bridge' because:

1. velocity of K⁺ is greater than that of ${\mathrm{NO}}_3^{-}$

2. velocity of ${\mathrm{NO}}_3^{-}$ is greater than that of K⁺

3. Velocities of both K⁺ and ${\mathrm{NO}}_3^{-}$ are nearly the same

4. KNO₃ is highly soluble in water

A current is passed through two voltameters connected in series. The first voltmeter connected in series. The first voltmeter contains XSO₄(aq) while the second voltmeter contains Y₂SO₄(aq). The relative  atomic masses of X and Y are in the ratio of 2:1. The ration of the mass of X liberated to the mass of Y liberated is: 

1. 1:1

2. 1:2

3. 2:1

4. none of these

The mass of silver(eq. mass = 108) displaced by that quantity of current which displaced 5600 mL of hydrogen at STP is:

1. 54 g

2. 108 g

3. 5.4 g

4. none of these

A silver cup is plated with silver by passing 965 coulomb of electricity. The amount of Ag deposited is:

1. 1.08 g

2. 1.0002 g

3. 9.89 g

4. 107.89 g

Which is the correct representation for Nernst equation ?

1. $E_{\mathrm{RP}} = E_{\mathrm{RP}}^{\circ }\mathit{ }+ \frac{0.059}{\mathrm{n}}\log \frac{\left[\mathrm{oxidant}\right]}{\left[\mathrm{reductant}\right]}$

2. $E_{\mathrm{OP}} = E_{\mathrm{OP}}^{\circ }\mathit{ }\mathit{-} \frac{0.059}{\mathrm{n}}\log \frac{\left[\mathrm{oxidant}\right]}{\left[\mathrm{reductant}\right]}$

3. $E_{\mathrm{OP}} = E_{\mathrm{OP}}^{\circ }\mathit{ }+ \frac{0.059}{\mathrm{n}}\log \frac{\left[\mathrm{reductant}\right]}{\left[\mathrm{oxidant}\right]}$

4. All of the above

When a copper wire is immersed in a solution of AgNO₃, the colour of solution becomes blue because copper:

1. Forms a soluble complex with AgNO₃

2. Is oxidised to Cu²⁺

3. Is reduced to Cu^2-

4. Splits up into atoic form and dissolves.

The specific conductance of a 0.1N KCl solution at 23$°\mathrm{C}$ is 0.012 ${\mathrm{\Omega }}^{-1}{\mathrm{cm}}^{-1}$. The resistance of cell containing the solution at the same temperature was found to be 55 $\mathrm{\Omega }$. The cell constant will be 
1. 0.142cm^-1

2. 0.66 cm^-1

3. 0.918 cm^-1

4. 1.12cm^-1

Given below are the half-cell reactions,

Mn²⁺ + 2e^-  $\to \; Mn; \; \; \; \; \; \; E0\; =\; -1.18V$

$$ \to \; 2Mn2+; \; E0\; =\; +1.51V$$

$$ E0 for\; 3\; Mn2+ \to \; 2\; Mn+3 \; +$$Mn will be:

$$ $ 1.\; -2.69V;\; the\; reaction\; will\; not\; occur$$$

$$ $ 2.\; -2.69V;\; the\; reaction\; will\; occur$$$

$$ $ $ 3.\; -0.33V;\; the\; reaction\; will\; not\; occur$$$$

$$ $ $ $ 4.\; -0.33V;\; the\; reaction\; will\; occur$$$$$