110 J of heat is added to a gaseous system, whose internal energy change is 40 J, then the amount of external work done is 

(1) 150 J

(2) 70 J

(3) 110 J

(4) 40 J

Which of the following is not thermodynamical function ?

(1) Enthalpy

(2) Work done

(3) Gibb's energy

(4) Internal energy

When the amount of work done is 333 cal and change in internal energy is 167 cal, then the heat supplied is -

(1) 166 cal

(2) 333 cal

(3) 500 cal

(4) 400 cal

First law thermodynamics states that

(1) System can do work

(2) System has temperature

(3) System has pressure

(4) Heat is a form of energy

A thermo-dynamical system is changed from state (P₁, V₁) to (P₂, V₂) by two different process. The quantity which will remain same will be

(1) ΔQ

(2) ΔW

(3) ΔQ + ΔW

(4) ΔQ – ΔW

If ΔQ and ΔW represent the heat supplied to the system and the work done on the system respectively, then the first law of thermodynamics can be written as 

(1) ΔQ = ΔU + ΔW

(2) ΔQ = ΔU – ΔW

(3) ΔQ = ΔW – ΔU

(4) ΔQ = –ΔU – ΔW

where ΔU is the internal energy

Which of the following can not determine the state of a thermodynamic system?

Which of the following is not a thermodynamics co-ordinate ?

(1) P

(2) T

(3) V

(4) R

The second law of thermodynamics states that in a cyclic process:

1. Work cannot be converted into heat

2. Heat cannot be converted into work

3. Work cannot be completely converted into heat

4. Heat cannot be completely converted into work

In a thermodynamic process, pressure of a fixed mass of a gas is changed in such a manner that the gas molecules absorb 30 J of heat and 10 J of work is done by the gas. If the initial internal energy of the gas was 40 J, then the final internal energy will be -

(1) 30 J

(2) 20 J

(3) 60 J

(4) 40 J