A solution of glucose (M.W = 180 g mol^–1) in water is 10 % w/w. The mole fraction of each component in the solution is:

1.	Mole fraction of glucose - 0.44; mole fraction of water - 0.56
2.	Mole fraction of glucose - 0.056; mole fraction of water - 0.944
3.	Mole fraction of glucose - 0.011; mole fraction of water - 0.99
4.	Mole fraction of glucose - 0.36; mole fraction of water - 0.64

An antifreeze solution is prepared from 222.6 g of ethylene glycol (C₂H₆O₂) and 200 g of water. The molality of the solution would be:

A sample of drinking water was contaminated with chloroform. The level of contamination was 15 ppm (by mass). The mass percent of chloroform is:

1. $15\times {10}^{-4}$

2. $1.5\times {10}^{-4}$

3. $0.15\times {10}^{-4}$

4. $15\times {10}^{-5}$

The type of molecular interactions in a solution of alcohol and water is:

The graph representing Henry's law is given below:

The value of the slope will be

Points A and B in the below-mentioned graph represent, respectively:

The law represented by given graph is -

The graph, amongst the following, representing positive deviation of vapour pressure is-

1.		2.
3.		4.	None of the above

The correct graph amongst the following, that represents the elevation in boiling point is:

1.
2.
3.
4.	None of the above.

The following solutions were prepared by dissolving 10 g of glucose (C₆H₁₂O₆) in 250 ml of water (P₁), 10 g of urea (CH₄N₂O) in 250 ml of water (P₂) and 10 g of sucrose (C₁₂H₂₂O₁₁) in 250 ml of water (P₃). The decreasing order of osmotic the pressure of these solutions is: