In the preparation of compounds of Xe, Bartlett had taken $O_2^{+}Pt{F}_6^{-}$ as a base compound. This is because

1. Both O₂ and Xe have same size.

2. Both O₂ and Xe have same electron gain enthalpy.

3. Both O₂ and Xe have almost same ionisation enthalpy.

4. Both Xe and O₂ are gases.

Reduction potentials of some ions are given below. Arrange them in decreasing order of oxidising power.

Ion                                                 $Cl{O}_4^{-}$                  $I{O}_4^{-}$                  $Br{O}_4^{-}$

Reduction potential $E^{⊝}/V$        $E^{⊝}=1.19 V$       $E^{⊝}=1.65 V$       $E^{⊝}=1.74 V$

1. $Cl{O}_4^{-}>I{O}_4^{-}>Br{O}_4^{-}$

2. $I{O}_4^{-}>Br{O}_4^{-}>Cl{O}_4^{-}$

3. $Br{O}_4^{-}>I{O}_4^{-}>Cl{O}_4^{-}$

4. $Br{O}_4^{-}>Cl{O}_4^{-}>I{O}_4^{-}$

Match the items of Columns I and II and mark the correct option.
     Column I                                                       Column II

(A) H₂SO₄                                              (i) Highest electron gain enthalpy
(B) CCl₃NO₂                                           (ii) Chalcogen
(C) Cl₂                                                   (iii) Tear gas
(D) Sulphur                                             (iv) Storage batteries

(1) A(iv) B(iii) C(i) D(ii)

(2) A(iii) B(iv) C(i) D(ii)

(3) A(iv) B(i) C(ii) D(iii)

(4) A(ii) B(i) C(iii) D(iv)

Match the items of Columns I and II and mark the correct option.
     

                      Column I                                                  Column II

(A) Its partial hydrolysis does not                                        (i) He
    change oxidation state of central atom

(B) It is used in modern diving apparatus                             (ii) XeF₆

(C) It is used to provide inert atmosphere                            (iii) XeF₄
     for filling electrical bulbs

(D) Its central atom is in sp³d² hybridisation                        (iv) Ar

1. A(i) B(iv) C(ii) D(iii)

2. A(i) B(ii) C(iii) D(iv)

3. A(ii) B(i) C(iv) D(iii)

4. A(i) B(iii) C(ii) D(iv)

The chemical formula of 'laughing gas' is

1.  NO

2.  ${\mathrm{N}}_2\mathrm{O}$

3.  ${\mathrm{N}}_2{\mathrm{O}}_4$

4.  ${\mathrm{N}}_2{\mathrm{O}}_5$

1. (X) = Phosphorous acid, (Y) = Metaphosphoric acid

2. (X) = Pyrophosphoric acid, (Y) = Metaphosphoric acid

3. (X) = Metaphosphoric acid, (Y) = Pyrophosphoric acid

4. (X) = Metaphosphoric acid, (Y) = Phosphene gas

Which one of the following compounds on strong heating evolves ammonia gas ?

1. ${\left({\mathrm{NH}}_4\right)}_{2}S{O}_4$

2. ${\mathrm{HNO}}_3$

3. ${\left({\mathrm{NH}}_4\right)}_{2}C{r}_2{O}_7$

4. ${\mathrm{NH}}_4{\mathrm{NO}}_3$

Match List - I with List - II

1. I-a, II-b, III-d, IV-c

2. I-b, II-c, III-a, IV-d

3. I-a, II-d, III-c, IV-b

4. I-a, II-c, III-b, IV-d 

Ammonia can be dried by

1. conc. ${\mathrm{H}}_2{\mathrm{SO}}_4$

2. ${\mathrm{P}}_4{\mathrm{O}}_{10}$

3. CaO

4. anhydrous ${\mathrm{CaCl}}_2$

There is no S-S bond in

1. ${\mathrm{S}}_2{\mathrm{O}}_4^{2-}$

2. ${\mathrm{S}}_2{\mathrm{O}}_5^{2-}$

3. ${\mathrm{S}}_2{\mathrm{O}}_3^{2-}$

4. ${\mathrm{S}}_2{\mathrm{O}}_7^{2-}$