A uniform rod of mass m and length L pivoted from its one end is executing SHM with time period T. If rod suddenly breaks from the middle while passing through its mean position, then the time period of oscillation of remaining half part will be
1. 2T
2.
3.
4.
A pendulum oscillates about its mean position \(\mathrm{C}.\) The position where the speed of the bob becomes maximum is: (ignore all dissipative forces)
1. | \(\mathrm{A}\) | 2. | \(\mathrm{B}\) |
3. | \(\mathrm{C}\) | 4. | \(\mathrm{D}\) |
1. | \(T_1<T_2\) | 2. | \(T_1>T_2\) |
3. | \(T_1=T_2\) |
4. | \(T_1= 2T_2\) |
The position x (in centimeter) of a simple harmonic oscillator varies with time t (in second) as . The magnitude of the maximum acceleration of the particle in is:
1. /2
2. /4
3. /2
4. /4
A horizontal platform is executing simple harmonic motion in the vertical direction with frequency f. A block of mass m is placed on the platform. What is the maximum amplitude of the SHM, so that the block is not detached from it?
1.
2.
2.
4.
A body at the end of a spring executes S.H.M. with a period while the corresponding period for another spring is . If the period of oscillation with two springs in series is T, then:
1.
2.
3.
4.
A body is executing linear S.H.M. At a position x, its potential energy is , and at a position y, its potential energy is . The potential energy at the position (x + y) is
1.
2.
3.
4.
The equation of a particle executing simple harmonic motion is (where t is in seconds and y is in meters). The initial phase of the particle is:
1.
2.
3.
4.
An ideal spring-mass system has a time period of vibration T. If the spring is cut into 4 identical parts and same mass oscillates with one of these parts, then the new time period of vibration will be
1.
2. T
3.
4. 2T
The equation of a particle executing simple harmonic motion is Displacement y from the mean position where acceleration becomes zero is: (y is in cm and t is in second)
1. 2 cm
2. 0
3. cm
4. cm