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Q. No.A particle \((P)\) of mass \(m\) is placed on the axis of a uniform circular ring of radius \(R\) and mass \(M.\) Its distance \((OP)\) from the centre \((O)\) of the ring is equal to \(R.\) Let the net gravitational field at the centre of the ring be \(g.\) Then, the gravitational potential energy of the interaction of the system is:
| 1. | \(-MgR\) | 2. | \(-mgR\) |
| 3. | \(\dfrac{-MgR}{\sqrt2}\) | 4. | \(\dfrac{-mgR}{\sqrt2}\) |
Subtopic: Gravitational Potential Energy |
Level 3: 35%-60%
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