Q. No.| Assertion (A): | In a simple battery circuit, the point of the lowest potential is positive terminal of the battery. |
| Reason (R): | The current flows towards the point of the higher potential, as it does in such a circuit from the negative to the positive terminal. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | Both (A) and (R) are False. |
| 1. | \(0.5~\Omega\) | 2. | \(0.8~\Omega\) |
| 3. | \(1.0~\Omega\) | 4. | \(0.2~\Omega\) |
| 1. | \(2~\Omega\) | 2 | \(1~\Omega\) |
| 3. | \(0.5~\Omega\) | 4. | zero |
A voltmeter of resistance \(660~\Omega\) reads the voltage of a very old cell to be \(1.32\) V while a potentiometer reads its voltage to be \(1.44\) V. The internal resistance of the cell is:
1. \(30~\Omega\)
2. \(60~\Omega\)
3. \(6~\Omega\)
4. \(0.6~\Omega\)
A current of \(2~\text{A}\) flows through a \(2~\Omega\) resistor when connected across a battery. The same battery supplies a current of \(0.5~\text{A}\) when connected across a \(9~\Omega\) resistor. The internal resistance of the battery is:
| 1. | \(\dfrac{1}{3}~\Omega\) | 2. | \(\dfrac{1}{4}~\Omega\) |
| 3. | \(1~\Omega\) | 4. | \(0.5~\Omega\) |
A set of '\(n\)' equal resistors, of value '\(R\)' each, are connected in series to a battery of emf '\(E\)' and internal resistance '\(R\)'. The current drawn is \(I.\) Now, if '\(n\)' resistors are connected in parallel to the same battery, then the current drawn becomes \(10I.\) The value of '\(n\)' is:
1. \(10\)
2. \(11\)
3. \(20\)
4. \(9\)
For a cell, the terminal potential difference is \(2.2~\text V\) when the circuit is open and reduces to \(1.8~\text V\) when the cell is connected to the resistance of \(R = 5~\Omega.\) The internal resistance of cell (\(r\)) is:
| 1. | \(\dfrac{10}{9}~ \Omega\) | 2. | \(\dfrac{9}{10}~ \Omega\) |
| 3. | \(\dfrac{11}{9}~ \Omega\) | 4. | \(\dfrac{5}{9}~ \Omega\) |
2. \(-r\) and \(E\)
| 1. | \(1\) A | 2. | \(2\) A |
| 3. | \(4\) A | 4. | Infinite |
A battery is charged at a potential of \(15\) V for \(8\) hours when the current flowing is \(10\) A. The battery on discharge supplies a current of \(5\) A for \(15\) hours. The mean terminal voltage during discharges is \(14\) V. The "Watt hour" efficiency of the battery is:
1. \(80\%\)
2. \(90\%\)
3. \(87.5\%\)
4. \(82.5\%\)
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