The electric field at the equator of a dipole is \(E.\) If the strength of the dipole and distance are now doubled, then the electric field will be:

1. \(E/2\) 2. \(E/8\)
3. \(E/4\) 4. \(E\)

Subtopic:  Electric Dipole |
 66%
From NCERT
AIPMT - 1998
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The unit of permittivity of free space \(\varepsilon_0\) is:
1. Newton metre2 / Coulomb2
2. Coulomb2 /Newton metre2
3. Coulomb2/ (Newton metre)2
4. Coulomb/Newton metre 

Subtopic:  Coulomb's Law |
 72%
From NCERT
AIPMT - 2004
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In Millikan oil drop experiment, a charged drop falls with a terminal velocity \(v\). If an electric field \(E\) is applied vertically upwards it moves with terminal velocity \(2v\) in upward direction. If electric field reduces to \(\frac{E}{2}\) then its terminal velocity will be:
1. \(\frac{v}{2}\)
2. \(v\)
3. \(\frac{3v}{2}\)
4. \(2v\)

Subtopic:  Electric Field |
From NCERT
AIPMT - 1999
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If \(10^9\) electrons move out of a body to another body every second, how much time approximately is required to get a total charge of \(1\)on the other body?
1. \(200\) years
2. \(100\) years
3. \(150\) years
4. \(250\) years

Subtopic:  Electric Charge |
 57%
From NCERT
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A charge \(q\) is placed in a uniform electric field \(E.\) If it is released, then the kinetic energy of the charge after travelling distance \(y\) will be:

1. \(qEy\) 2. \(2qEy\)
3. qEy2 4. qEy
Subtopic:  Electric Field |
 76%
From NCERT
AIPMT - 1998
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The electric field at a distance \(\frac{3R}{2}\) from the centre of a charged conducting spherical shell of radius \(R\) is \(E\). The electric field at a distance \(\frac{R}{2}\) from the centre of the sphere is:
1. \(E\)
2. \(\frac{E}{2}\)
3. \(\frac{E}{3}\)
4. zero
 

Subtopic:  Gauss's Law |
 84%
From NCERT
AIPMT - 2010
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The figure shows electric field lines in which an electric dipole p is placed as shown. Which of the following statements is correct?
                      

1. The dipole will not experience any force.
2. The dipole will experience a force towards the right.
3. The dipole will experience a force towards the left.
4. The dipole will experience a force upwards.

Subtopic:  Electric Dipole |
From NCERT
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The acceleration of an electron due to the mutual attraction between the electron and a proton when they are \(1.6~\mathring{A}\) apart is:
\(\frac{1}{4 \pi \varepsilon_0}=9 \times 10^9~ \text{Nm}^2 \text{C}^{-2}\) )

1. \( 10^{24} ~\text{m/s}^2\) 2 \( 10^{23} ~\text{m/s}^2\)
3. \( 10^{22}~\text{m/s}^2\) 4. \( 10^{25} ~\text{m/s}^2\)
Subtopic:  Coulomb's Law |
 75%
From NCERT
NEET - 2020
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The electric field at a point on the equatorial plane at a distance \(r\) from the centre of a dipole having dipole moment \(\overrightarrow{P}\) is given by:
(\(r\gg\) separation of two charges forming the dipole, \(\varepsilon_{0} =\) permittivity of free space) 

1. \(\overrightarrow{E}=\frac{\overrightarrow{P}}{4\pi \varepsilon _{0}r^{3}}\)  2. \(\overrightarrow{E}=\frac{2\overrightarrow{P}}{\pi \varepsilon _{0}r^{3}}\)
3. \(\overrightarrow{E}=-\frac{\overrightarrow{P}}{4\pi \varepsilon _{0}r^{2}}\) 4. \(\overrightarrow{E}=-\frac{\overrightarrow{P}}{4\pi \varepsilon _{0}r^{3}}\)
Subtopic:  Electric Dipole |
 62%
From NCERT
NEET - 2020
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Refer to the arrangement of charges in the figure and a Gaussian surface of radius \(R\) with \(Q\) at the centre. Then:

a. total flux through the surface of the sphere is \(\frac{-Q}{\varepsilon_0}\).
b. field on the surface of the sphere is \(\frac{-Q}{4\pi \varepsilon_0 R^2}.\)
c. flux through the surface of the sphere due to \(5Q\) is zero.
d. field on the surface of the sphere due to \(-2Q\) is the same everywhere.

Choose the correct statement(s): 
1. (a) and (d)
2. (a) and (c)
3. (b) and (d)
4. (c) and (d)

Subtopic:  Gauss's Law |
 71%
From NCERT
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