A stone projected with a velocity \(u\) at an angle \(\theta\) with the horizontal reaches maximum height \(H_1\). When it is projected with velocity \(u\) at an angle \(\frac{\pi}{2}-\theta\) with the horizontal, it reaches maximum height \(H_2\). The relation between the horizontal range of the projectile \(R\) and \(H_1\) & \(H_2\) is: 

1. \(R=4 \sqrt{H_1 H_2} \) 2. \(R=4\left(H_1-H_2\right) \)
3. \(R=4\left(H_1+H_2\right) \) 4. \(R=\frac{H_1{ }^2}{H_2{ }^2}\)

Subtopic:  Projectile Motion |
 83%
From NCERT
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A cricketer can throw a ball to a maximum horizontal distance of \(100~\text{m}\). With the same effort, he throws the ball vertically upwards. The maximum height attained by the ball is: 
1. \(100~\text{m}\)
2. \(80~\text{m}\)
3. \(60~\text{m}\)
4. \(50~\text{m}\)

Subtopic:  Projectile Motion |
 75%
From NCERT
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The horizontal range of a projectile is \(4 \sqrt{3}\) times its maximum height. Its angle of projection will be:
1. \(45^{\circ}\)
2. \(60^{\circ}\)
3. \(90^{\circ}\)
4. \(30^{\circ}\)

Subtopic:  Projectile Motion |
 73%
From NCERT
PMT - 2003
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Four bodies \(P\), \(Q\), \(R\) and \(S\) are projected with equal velocities having angles of projection \(15^{\circ},\) \(30^{\circ},\)\(45^{\circ},\) and \(60^{\circ}\) with the horizontal respectively. The body having the shortest range is? 

1. \(P\) 2. \(Q\)
3. \(R\) 4. \(S\)
Subtopic:  Projectile Motion |
 73%
From NCERT
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At the top of the trajectory of a projectile, the directions of its velocity and acceleration are:

1. perpendicular to each other
2. parallel to each other
3. inclined to each other at an angle of \(45^\circ\)
4. antiparallel to each other
Subtopic:  Projectile Motion |
 85%
From NCERT
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The coordinates of a moving particle at any time \(t\) are given by \(x= \alpha t^3\) and \(y = \beta t^3\). The speed of the particle at time \(t\) is given by:

1. \(\sqrt{\alpha^{2} + \beta^{2}}\) 2. \(3t \sqrt{\alpha^{2} + \beta^{2}}\)
3. \(3t^{2} \sqrt{\alpha^{2} +\beta^{2}}\) 4. \(t^{2} \sqrt{\alpha^{2} +\beta^{2}}\)
Subtopic:  Speed & Velocity |
 78%
From NCERT
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If the equation for the displacement of a particle moving on a circular path is given by \(\theta = 2t^3 + 0.5\) where \(\theta\) is in radians and \(t\) in seconds, then the angular velocity of the particle after \(2\) sec from its start is:
1. \(8\) rad/sec
2. \(12\) rad/sec
3. \(24\) rad/sec
4. \(36\) rad/sec

Subtopic:  Circular Motion |
 81%
From NCERT
AIIMS - 1998
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A particle moves with constant speed \(v\) along a circular path of radius \(r\) and completes the circle in time \(T\). The acceleration of the particle is:
1. \(2\pi v / T\)
2. \(2\pi r / T\)
3. \(2\pi r^2 / T\)
4. \(2\pi v^2 / T\)

Subtopic:  Circular Motion |
 61%
From NCERT
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What is the value of linear velocity if \(\overrightarrow{\omega} = 3\hat{i} - 4\hat{j} + \hat{k}\) and \(\overrightarrow{r} = 5\hat{i} - 6\hat{j} + 6\hat{k}\) :

1. \(6 \hat{i}+2 \hat{j}-3 \hat{k} \)           
2. \(-18 \hat{i}-13 \hat{j}+2 \hat{k} \)
3. \(4 \hat{i}-13 \hat{j}+6 \hat{k}\)
4. \(6 \hat{i}-2 \hat{j}+8 \hat{k}\)
Subtopic:  Circular Motion |
 85%
From NCERT
PMT - 2000
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A particle moves with constant angular velocity in a circle. During the motion its:

1. Energy is conserved
2. Momentum is conserved
3. Energy and momentum both are conserved
4. None of the above is conserved

Subtopic:  Circular Motion |
From NCERT
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