The scalar product of two vectors is 8 and the magnitude of vector product is 83. The angle between them is:

(1)  30°

(2)  60°

(3)  120°

(4)  150°

Subtopic:  Vector Product |
 73%
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Given: a+b+c=0. Out of the three vectors a, b and c two are equal in magnitude. The magnitude of the third vector is 2 times that of either of the two having equal magnitude. The angles between the vectors are:

(A)  90°, 135°, 135°

(B)  30°, 60°, 90°

(C)  45°, 45°, 90°

(D)  45°, 60°, 90°

Subtopic:  Resultant of Vectors |
 56%
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Vector A is of length 2 cm and is 60° above the x-axis in the first quadrant. Vector B is of length 2 cm and 60° below the x-axis in the fourth quadrant. The sum A+B is a vector of magnitude -

(A)  2 along + y-axis

(B)  2 along + x-axis

(C)  1 along - x-axis

(D)  2 along - x-axis

Subtopic:  Resultant of Vectors |
 81%
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Six forces, 9.81 N each, acting at a point are coplanar. If the angle between neighboring forces are equal, then the resultant is

(1)  0 N

(2)  9.81 N

(3)  2×9.81 N

(4)  3×9.81 N

Subtopic:  Resultant of Vectors |
 81%
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Temperature of a body varies with time as T=T0+at2+b sintK, where T0 is the temperature in Kelvin at t=0 sec & a=2/π K/s2 & b=-K, then the rate of change of temperature dTdt at t=π sec is:
1. \(8~\text{K}\)
2. \(80~\text{K}\)
3. \(8~\text{K/sec}\)
4. \(80~\text{K/sec}\)

Subtopic:  Differentiation |
 57%
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If the distance 's' travelled by a body in time 't' is given by s=at+bt2 then the acceleration equals

(1)  2at3+2b

(2)  2st3

(3)  2b-2at3

(4)  st2

Subtopic:  Differentiation |
 74%
From NCERT
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The velocity of a particle moving on the x-axis is given by v=x2+x where v is in m/s and x is in m. Find its acceleration in m/s2 when passing through the point x=2m.

1.  0

2.  5

3.  11

4.  30

Subtopic:  Differentiation |
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A particle moves in the XY plane and at time t is at the point whose coordinates are t2, t3-2t. Then at what instant of time, will its velocity and acceleration vectors be perpendicular to each other?

(1)  1/3 sec

(2)  2/3 sec

(3)  3/2 sec

(4)  never

Subtopic:  Scalar Product |
 62%
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A particle is moving along positive x-axis. Its position varies as x=t3-3t2+12t+20, where x is in meters and t is in seconds.

Initial acceleration of the particle is

(A)  Zero

(B)  1 m/s2

(C)  -3 m/s2

(D)  -6 m/s2

Subtopic:  Differentiation |
 76%
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Two forces F1=2i^+2j^ N and F2=3j^+4k^ N are acting on a particle.

The resultant force acting on particle is:

(A)  2i^+5j^+4k^

(B)  2i^-5j^-4k^

(C)  i^-3j^-2k^

(D)  i^-j^-k^

Subtopic:  Resultant of Vectors |
 84%
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