A particle is moving westward with a velocity vi=5 m/s. Its velocity changed to vf=5m/s northward. The change in velocity vector V=vf-vi is:

(1)  52 m/s  towards north east

(2)  5 m/s  towards north west

(3)  zero

(4)  52 m/s towards north west

Subtopic:  Resultant of Vectors |
 61%
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Consider east as positive x-axis, north as positive y-axis and vertically upward direction as z-axis. A helicopter first rises up to an altitude of 100 m than flies straight in north 500 m and then suddenly takes a turn towards east and travels 1000 m east. What is position vector of helicopter. (Take starting point as origin)

(1)  1000 i^-500 j^+100 k^

(2)  1000 i^+500 j^-100 k^

(3)  1000 i^+500 j^+100 k^

(4)  -1000 i^+500 j^+100 k^

Subtopic:  Resolution of Vectors |
 77%
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A force F=6i^-8j^+10k^ Newton produces acceleration 1 m/s2 in a body. The mass of the body is (in kg)

(1)  6i^-8j^+10k^

(2)  100

(3)  102

(4)  10

Subtopic:  Newton's Laws |
 76%
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Given the vectors

                         A=2i^+3j^-k^
                         B=3i^-2j^-2k^
&                      C=pi^+pj^+2pk^

Find the angle between A-B & C

(A)  θ=cos-123

(B)  θ=cos-132

(C)  θ=cos-123

(D)  none of these

Subtopic:  Scalar Product |
 53%
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The vector having a magnitude of 10 and perpendicular to the vector 3i^-4j^ is- 

1. 4i^-3j^

2. 52 i^-52 j^

3. 8i^+6j^

4.  8i^-6j^

Subtopic:  Scalar Product |
 61%
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A force F=3i^+cj^+2k^ acting on a particle causes a displacement d=-4i^+2j^+3k^. If the work done is 6J then the value of 'c' is- [Given: W=F.d]

1. 12 

2. 0

3. 6

4. 1

Subtopic:  Scalar Product |
 82%
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A particle moving along a straight line according to the law x=At+Bt2+Ct3, where x is its position measured from a fixed point on the line and t is the time elapsed till it reaches position x after starting from the fixed point. Here A, B and C are positive constants.

(1)  Its velocity at t=0 is A

(2)  Its acceleration at t=0 is B

(3)  Its velocity at t=0 is B

(4)  Its acceleration at t=0 is C

Subtopic:  Differentiation |
 80%
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If the velocity of a particle moving on x-axis is given by v=3t2-12t+6. At which time is the acceleration of particle zero?

1.  2 sec

2.  2+2 sec

3.  2-2 sec

4.  zero

Subtopic:  Differentiation |
 84%
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Momentum of a body moving in a straight line is p=t2+2t+1 kg m/s. Find the force acting on a body at t=2 sec

(1)  6 N

(2)  8 N

(3)  4 N

(4)  2 N

Subtopic:  Newton's Laws |
 83%
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A particle moves along straight line such that at time t its position from a fixed point O on the line is x=3t2-2. The velocity of the particle when t=2 is:

(A)  8 ms-1

(B)  4 ms-1

(C)  12 ms-1

(D)  0

Subtopic:  Differentiation |
 90%
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