Reaction of HBr with propene in the presence of peroxide gives

1. iso-propyl bromide

2. 3-bromo propane

3. allyl bromide

4. n-propyl bromide

In the reaction, ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_3\stackrel{\mathrm{Oxidation}}{\to }$A $\stackrel{\mathrm{NaOH}}{\to }$B$\underset{∆}{\overset{\mathrm{Soda} \mathrm{lime}}{\to }}$C 

the product C is:

1. ${\mathrm{C}}_6{\mathrm{H}}_5\mathrm{OH}$ 

2. ${\mathrm{C}}_6{\mathrm{H}}_6$

3. ${\mathrm{C}}_6{\mathrm{H}}_5\mathrm{COONa}$

4. ${\mathrm{C}}_6{\mathrm{H}}_5\mathrm{ONa}$

The compound formed when acetylene is passed through dilute sulphuric acid in the presence of mercury(II) sulphate is:

1. Ether

2. Ketone

3. Acetic acid

4. Acetaldehyde

Why are acetylenic hydrogens acidic?

A compound is treated with ${\mathrm{NaNH}}_2$ to give sodium salt. Identify the compound.

1. ${\mathrm{C}}_2{\mathrm{H}}_2$ 

2. ${\mathrm{C}}_6{\mathrm{H}}_6$

3. ${\mathrm{C}}_2{\mathrm{H}}_6$ 

4. ${\mathrm{C}}_2{\mathrm{H}}_4$

Which alkene on ozonolysis gives 
 $CH_3CH_2CHO$ and  $CH_3CCH_3\\ ~~~~~~~~||\\ ~~~~~~~~O$   

1.
2.	$\mathrm {CH_3CH_2CH=CHCH_2CH_3}$
3.	$\mathrm {CH_3CH_2CH=CHCH_3}$
4.

1. 

2. ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{CH}={\mathrm{CHCH}}_2{\mathrm{CH}}_3$

3. ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{CH}={\mathrm{CHCH}}_3$

4.    
 

Hydroxylation of propyne in the presence of ${\mathrm{HgSO}}_4/{\mathrm{H}}_2{\mathrm{SO}}_4$ is initiated by the attack of:

1. carbene 

2. free radical

3. electrophile

4. nucleophile

Which products are obtained from the ozonolysis of buta-1,3-diene?

1. Formaldehyde and glyoxal  
2. Acetaldehyde and glyoxal  
3. Carbon dioxide and glyoxal  
4. Formaldehyde, glyoxal, and acetaldehyde

Which is the most suitable reagent among the following to distinguish compound (III) from rest of the compounds?

I. ${\mathrm{CH}}_3-\mathrm{C}\equiv \mathrm{C}-{\mathrm{CH}}_3$

II. ${\mathrm{CH}}_3-{\mathrm{CH}}_2-{\mathrm{CH}}_2-{\mathrm{CH}}_3$

III. ${\mathrm{CH}}_3-{\mathrm{CH}}_2-\mathrm{C}\equiv \mathrm{CH}$

IV. ${\mathrm{CH}}_3-\mathrm{CH}={\mathrm{CH}}_2$