The momentum of a photon of energy hv will be

(1) hv     

(2) hv/c

(3) hvc     

(4) h/v

If the momentum of a photon is p, then its frequency is

(1) $\frac{\mathrm{ph}}{\mathrm{c}}$           

(2) $\frac{\mathrm{pc}}{\mathrm{h}}$

(3) $\frac{\mathrm{mh}}{\mathrm{c}}$           

(4) $\frac{\mathrm{mc}}{\mathrm{h}}$

where m is the rest mass of the photon

An AIR station is broadcasting the waves of wavelength 300 metres. If the radiating power of the transmitter is 10 kW, then the number of photons radiated per second is

(1) $1.5\times {10}^{29}$             

(2) $1.5\times {10}^{31}$

(3) $1.5\times {10}^{33}$             

(4) $1.5\times {10}^{35}$

The energy of a photon is E = hv and the momentum of photon $\mathrm{p}=\frac{\mathrm{h}}{\mathrm{\lambda }}$, then the velocity of photon will be

(1) E/p                     

(2) Ep

(3)  ${\left(\frac{\mathrm{E}}{\mathrm{P}}\right)}^2$                 

(4) $3\times {10}^8 \mathrm{m}/\mathrm{s}$

The approximate wavelength of a photon of energy 2.48 eV is 
(1) 500 Å                   

(2) 5000 Å

(3) 2000 Å                   

(4) 1000 Å

Wavelength of a 1 keV photon is $1.24\times {10}^{-9}m$. What is the frequency of 1 MeV photon?

1. $1.24\times {10}^{15} \mathrm{Hz}$      
2.  $2.4\times {10}^{20} \mathrm{Hz}$
3. $1.24\times {10}^{18} \mathrm{Hz}$      
4. $2.4\times {10}^{23} \mathrm{Hz}$

What is the momentum of a photon having frequency $1.5\times {10}^{13} \mathrm{Hz}$?
(a) $3.3\times {10}^{-29} \mathrm{kg} \mathrm{m}/\mathrm{s}$                (b) $3.3\times {10}^{-34} \mathrm{kg} \mathrm{m}/\mathrm{s}$
(c) $6.6\times {10}^{-34} \mathrm{kg} \mathrm{m}/\mathrm{s}$                (d) $6.6\times {10}^{-30} \mathrm{kg} \mathrm{m}/\mathrm{s}$

The energy of a photon of light of wavelength 450 nm is

(1) $4.4\times {10}^{-19} \mathrm{J}$             

(2) $2.5\times {10}^{-19} \mathrm{J}$

(3) $1.25\times {10}^{-17} \mathrm{J}$            

(4) $2.5\times {10}^{-17} \mathrm{J}$