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The de-Broglie wavelength of an electron having 80 eV of energy is nearly:
(1 eV=1.6×1019 J, Mass of electron =9×1031 kg Plank’s constant =6.6×1034 J-s)
1. 140 ˚A
2. 0.14 ˚A
3. 14 ˚A
4. 1.4 ˚A

Subtopic:  De-broglie Wavelength |
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If the following particles are moving at the same velocity, then which among them will have the maximum de-Broglie wavelength?
1. Neutron               
2. Proton
3. β -particle             
4. α -particle

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If an electron and a photon propagate in the form of waves having the same wavelength, it implies that they have the same 
(1) Energy             

(2) Momentum

(3) Velocity             

(4) Angular momentum

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The de-Broglie wavelength is proportional to 
(1) λ1v               

(2) λ1m

(3) λ1p               

(4) λp

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Particle nature and wave nature of electromagnetic waves and electrons can be shown by 

(1) Electron has small mass, deflected by the metal sheet

(2) X-ray is diffracted, reflected by thick metal sheet

(3) Light is refracted and defracted

(4) Photoelectricity and electron microscopy

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The de-Broglie wavelength of a particle moving with a velocity 2.25\times 10^{8} m/s is equal to the wavelength of the photon. What is the ratio of the kinetic energy of the particle to the energy of the photon? (velocity of light is 3\times 10^{8} m/s)
1. \frac{1}{8} 2. \frac{3}{8}
3. \frac{5}{8} 4. \frac{7}{8}
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The speed of an electron having a wavelength of 10-10m is

(a) 7.25×106 m/s                   (b) 6.26×106 m/s 
(c) 5.25×106 m/s                   (d) 4.24×106 m/s

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The kinetic energy of electron and proton is 10-32 J. Then the relation between their de-Broglie wavelengths is

(1) λp<λe                 

(2) λp>λe

(3) λp=λe                 

(4) λp=2λe

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The de-Broglie wavelength of a particle accelerated with 150 volt potential is 10-10 m. If it is accelerated by 600 volts p.d., its wavelength will be
(1) 0.25 Å                 

(2) 0.5 Å

(3) 1.5 Å                   

(4) 2 Å

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The de-Broglie wavelength associated with a hydrogen molecule moving with a thermal velocity of 3 km/s will be
(1) 1 Å                     

(2) 0.66 Å

(3) 6.6 Å                 

(4) 66 Å

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