A body is executing Simple Harmonic Motion. At a displacement x its potential energy is E1 and at a displacement y its potential energy is E2. The potential energy E at displacement x+y is 

(1)  E=E1+E2   

(2)  E=E1+E2

(3)   E=E1+E2           

(4)  None of these.

Subtopic:  Energy of SHM |
 56%
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In a simple pendulum, the period of oscillation T is related to length of the pendulum l as:
1. lT= constant
2. l2T= constant
3. lT2= constant
4. l2T2= constant

Subtopic:  Angular SHM |
 84%
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The kinetic energy of a particle executing S.H.M. is 16 J when it is in its mean position. If the amplitude of oscillations is 25 cm and the mass of the particle is 5.12 kg, the time period of its oscillation is -

(1) π5sec       

(2) 2π sec

(3) 20π sec   

(4) 5π sec

Subtopic:  Energy of SHM |
 66%
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A pendulum has time period T. If it is taken on to another planet having acceleration due to gravity half and mass 9 times that of the earth, then its time period on the other planet will be:

1. \(\sqrt{\mathrm{T}} \) 2. \(T \)
3. \(\mathrm{T}^{1 / 3} \) 4. \(\sqrt{2} \mathrm{~T}\)
Subtopic:  Angular SHM |
 82%
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A particle in SHM is described by the displacement equation xt=Acos ωt+θ. If the initial position of the particle is 1 cm and its initial velocity is πcm/s, what is its amplitude? (The angular frequency of the particle is π s-1)

(1)   1 cm       

(2)  2 cm

(3)    2 cm     

(4)   2.5 cm

Subtopic:  Simple Harmonic Motion |
 58%
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A simple pendulum hanging from the ceiling of a stationary lift has a time period T1. When the lift moves downward with constant velocity, then the time period becomes T2. It can be concluded that: 

1. \(T_2 ~\text{is infinity} \) 2. \(\mathrm{T}_2>\mathrm{T}_1 \)
3. \(\mathrm{T}_2<\mathrm{T}_1 \) 4. \(T_2=T_1\)
Subtopic:  Angular SHM |
 60%
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If the length of a pendulum is made 9 times and mass of the bob is made 4 times, then the value of time period will become:

1. 3T

2. 3/2T

3. 4T

4. 2T

Subtopic:  Angular SHM |
 82%
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A simple harmonic wave having an amplitude a and time period T is represented by the equation y=5 sinπt+4m Then the value of amplitude (a) in (m) and time period  (T) in second are       

(1)   a=10, T=2   

(2) a=5, T=1

(3)    a=10, T=1    

(4) a=5, T=2

Subtopic:  Simple Harmonic Motion |
 85%
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The period of a simple pendulum measured inside a stationary lift is found to be T. If the lift starts accelerating upwards with acceleration of g/3 then the time period of the pendulum is

(1) T3

(2) T3

(3) 32T

(4) 3T

Subtopic:  Simple Harmonic Motion |
 87%
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The time period of a simple pendulum of length L as measured in an elevator descending with acceleration g3 is

(1) 2π3Lg

(2) π3Lg

(3) 2π3L2g

(4) 2π2L3g

Subtopic:  Simple Harmonic Motion |
 83%
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