An SHM has an amplitude aa and a time period T.T. The maximum velocity will be:
1. 4aT4aT       
2. 2aT2aT
3. 2πT2πT
4. 2aπT2aπT

Subtopic:  Simple Harmonic Motion |
 91%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

Two particles PP and QQ start from origin and execute Simple Harmonic Motion along x-x-axis with same amplitude but with periods 33 seconds and 66 seconds respectively. The ratio of the velocities of PP and QQ when they meet is:
1. 1:21:2
2. 2:12:1
3. 2:32:3
4. 3:23:2
Subtopic:  Simple Harmonic Motion |
 85%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

The angular velocities of three bodies in simple harmonic motion are ω1,ω2,ω3ω1,ω2,ω3 with their respective amplitudes as A1,A2,A3A1,A2,A3. If all the three bodies have same mass and maximum velocity, then

1. A1ω1=A2ω2=A3ω3A1ω1=A2ω2=A3ω3       
2.  A1ω12=A2ω22=A3A32A1ω12=A2ω22=A3A32
3. A12ω1=A22ω2=A32ω3A12ω1=A22ω2=A32ω3   
4. A12ω12=A22ω22=A2A12ω12=A22ω22=A2  

Subtopic:  Simple Harmonic Motion |
 89%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

advertisementadvertisement

The amplitude of a particle executing SHM is 4 cm. At the mean position the speed of the particle is 16 cm/sec. The distance of the particle from the mean position at which the speed of the particle becomes 83cm/sec83cm/sec will be

1.   23cm23cm             

2.  3cm3cm

3.  1 cm                   

4.  2 cm

Subtopic:  Simple Harmonic Motion |
 70%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

The maximum velocity of a simple harmonic motion represented by y=3 sin (100t+π6)y=3 sin (100t+π6) is given by

1. 300       

2.  3π63π6

3. 100         

4.  π6π6

Subtopic:  Simple Harmonic Motion |
 93%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

The displacement equation of a particle is x=3sin 2t+4cos 2t x=3sin 2t+4cos 2t  The amplitude and maximum velocity will be respectively

1. 5, 10      

2. 3, 2

3. 4, 2       

4. 3, 4

Subtopic:  Simple Harmonic Motion |
 90%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

advertisementadvertisement

The instantaneous displacement of a simple pendulum oscillator is given by x=A cos (ωt+π4)x=A cos (ωt+π4) . Its speed will be maximum at time

1. π4ωπ4ω      

2. π2ωπ2ω

3. πωπω                

4. 2πω2πω

Subtopic:  Simple Harmonic Motion |
 61%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

The amplitude of a particle executing S.H.M. with frequency of 60 Hz is 0.01 m. The maximum value of the acceleration of the particle is

1  144π2m/sec2144π2m/sec2       
2  144m/sec2144m/sec2

3. 144π2m/sec2144π2m/sec2          
4. 288π2m/sec2288π2m/sec2   

Subtopic:  Simple Harmonic Motion |
 88%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

A particle moving along the x-axis executes simple harmonic motion, then the force acting on it is given by

1.  – A Kx           

2.  A cos (Kx)

3.  A exp (– Kx

4.  A Kx

Subtopic:  Simple Harmonic Motion |
 84%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

advertisementadvertisement

What is the maximum acceleration of the particle doing the SHM y=2sin[πt2+ϕ]y=2sin[πt2+ϕ] where 2 is in cm

1.  π2cm/s2π2cm/s2                
2.  π22cm/s2π22cm/s2
3.  π4cm/s2π4cm/s2             
4.  π4cm/s2π4cm/s2

Subtopic:  Simple Harmonic Motion |
 92%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch