The escape velocity for a rocket from the earth is \(11.2\) km/s. Its value on a planet where the acceleration due to gravity is double that on the earth and the diameter of the planet is twice that of the earth (in km/s) will be:

1. \(11.2\) 2. \(5.6\)
3. \(22.4\) 4. \(53.6\)

Subtopic:  Escape velocity |
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The escape velocity from the earth is about 11 km/second. The escape velocity from a planet having twice the radius and the same mean density as the earth is

(1) 22 km/sec                               (2) 11 km/sec

(3) 5.5 km/sec                               

(4) 15.5 km/sec

Subtopic:  Escape velocity |
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What should be the velocity of earth due to rotation about its own axis so that the weight at equator become 3/5 of initial value. Radius of earth on equator is 6400 km

 (a)  7.4×10-4 rad/sac             

 (b)  6.4×10-4 rad/sac

 (c)  7.8×10-4 rad/sac               

(d)  8.7×10-4 rad/sac 

Subtopic:  Acceleration due to Gravity |
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If g is the acceleration due to gravity at the earth's surface and r is the radius of the earth, the escape velocity for the body to escape out of the earth's gravitational field is:

(1) gr                                       

(2) 2gr

(3) g/r                                       

(4) r/g

Subtopic:  Escape velocity |
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The escape velocity of a projectile from the earth is approximately

(1)11.2 m/sec                            (2)112 km/sec

(3)11.2 km/sec                           (4)11200 km/sec

Subtopic:  Escape velocity |
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The escape velocity of a particle of mass m varies as:

(1) m2                                   

(2) m

(3) m0                                   

(4) m-1

Subtopic:  Escape velocity |
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Acceleration due to gravity is ‘g’ on the surface of the earth. The value of acceleration due to gravity at a height of 32 km above earth’s surface is (Radius of the earth = 6400 km)

(1) 0.9 g           

(2) 0.99g

(3) 0.8 g           

(4) 1.01 g

Subtopic:  Acceleration due to Gravity |
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The time period of a simple pendulum on a freely moving artificial satellite is

(1) Zero                           

(2) 2 sec

(3)  3 sec                          

(4)  Infinite

Subtopic:  Satellite |
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For the moon to cease as the earth's satellite, its orbital velocity has to be increased by a factor of:

1. \(2\) 2. \(\sqrt{2}\)
3. \(1/\sqrt{2}\) 4. \(4\)
Subtopic:  Orbital velocity |
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The height of a point vertically above the earth’s surface, at which the acceleration due to gravity becomes \(1\%\) of its value at the surface is: (Radius of the earth = \(R\))
1. \(8R\)
2. \(9R\)
3. \(10R\)
4. \(20R\)

Subtopic:  Acceleration due to Gravity |
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