The capacity of a parallel plate capacitor with no dielectric substance but with a separation of 0.4 cm is 2 μF. The separation is reduced to half and it is filled with a dielectric substance of value 2.8. The final capacity of the capacitor is
(1) 11.2 μF
(2) 15.6 μF
(3) 19.2 μF
(4) 22.4 μF
Two insulated metallic spheres of 3 μF and 5 μF capacitances are charged to 300 V and 500V respectively. The energy loss, when they are connected by a wire is
(1) 0.012 J
(2) 0.0218 J
(3) 0.0375 J
(4) 3.75 J
A charge of 40 μC is given to a capacitor having capacitance C = 10 μF. The stored energy in ergs is
(1) 80 × 10–6
(2) 800
(3) 80
(4) 8000
A parallel plate capacitor has plate area A and separation d. It is charged to a potential difference V0. The charging battery is disconnected and the plates are pulled apart to three times the initial separation. The work required to separate the plates is
(1)
(2)
(3)
(4)
The electric field between the plates of a parallel plate capacitor when connected to a certain battery is E0. If the space between the plates of the capacitor is filled by introducing a material of dielectric constant K without disturbing the battery connections, the field between the plates shall be
(1) K E0
(2) E0
(3)
(4) None of the above
If the distance between parallel plates of a capacitor is halved and dielectric constant is doubled then the capacitance
(1) Decreases two times
(2) Increases two times
(3) Increases four times
(4) Remain the same
If there are n capacitors each of capacitance C in parallel connected to V volt source, then the energy stored is equal to
1. CV
2.
3. CV2
4.
The unit of electric permittivity is
(1) Volt/m2
(2) Joule/coulomb
(3) Farad/m
(4) Henry/m
The work done in placing a charge of 8 × 10–18 coulomb on a condenser of capacity 100 micro-farad is
(1) 32× 10–32 Joule
(2) 16 × 10–32 Joule
(3) 3.1 × 10–26 Joule
(4) 4 × 10–10 Joule