Consider the charge configuration and spherical Gaussian surface as shown in the figure. While calculating the flux of the electric field over the spherical surface, the electric field will be due to: 

(1) q2 only

(2) Only the positive charges

(3) All the charges

(4) +q1 and – q1 only

Subtopic:  Gauss's Law |
 61%
From NCERT
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An electric dipole is put in north-south direction in a sphere filled with water. Which statement is correct ?

(1) Electric flux is coming towards sphere

(2) Electric flux is coming out of sphere

(3) Electric flux entering into sphere and leaving the sphere are same

(4) Water does not permit electric flux to enter into sphere

Subtopic:  Gauss's Law |
 80%
From NCERT
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The electric flux for Gaussian surface A that encloses the charged particles in free space is (given q1 = –14 nC, q2 = 78.85 nC, q3 = – 56 nC) 

(1) 103 Nm2 C–1

(2) 103 CN-1 m–2

(3) 6.32 × 103 Nm2 C–1

(4) 6.32 × 103 CN-1 m–2

Subtopic:  Gauss's Law |
 61%
From NCERT
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The electric intensity due to an infinite cylinder of radius R and having charge q per unit length at a distance r(r > R) from its axis is 

(1) Directly proportional to r2

(2) Directly proportional to r3

(3) Inversely proportional to r

(4) Inversely proportional to r2

Subtopic:  Electric Field |
 66%
From NCERT
PMT - 1993
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Two equal negative charges of charge \(-q\) are fixed at the points \((0,a)\) and \((0,-a)\) on the \(Y\text-\)axis. A positive charge \(Q\) is released from rest at the point \((2a,0)\) on the \(X\text-\)axis. The charge \(Q\) will:
1. execute simple harmonic motion about the origin.
2. move to the origin and remain at rest.
3. move to infinity.
4. execute oscillatory but not simple harmonic motion.
Subtopic:  Coulomb's Law |
 54%
From NCERT
PMT - 1996
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An electrostatic line of force in the xy plane is given by equation x2 + y2 = 1. A particle with unit positive charge, initially at rest at the point x = 1, y = 0 in the xy plane will -

1. Not move at all

2. Will move along straight line

3. Will move along the circular line of force

4. The data given in the question is contradictory

Subtopic:  Electric Field |
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A positively charged ball hangs from a silk thread. We put a positive test charge q0 at a point and measure F/q0, then it can be predicted that the electric field strength E 

(1) > F/q0

(2) = F/q0

(3) < F/q0

(4) Cannot be estimated

Subtopic:  Electric Field |
From NCERT
PMT - 1990
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A solid metallic sphere has a charge +3Q. Concentric with this sphere is a conducting spherical shell having charge –Q. The radius of the sphere is a and that of the spherical shell is (b > a). What is the electric field at a distance R(a < R < b) from the centre 

(1) Q2πε0R

(2) 3Q2πε0R

(3) 3Q4πε0R2

(4) 4Q4πε0R2 

Subtopic:  Electric Field |
 70%
From NCERT
PMT - 1995
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A point charge \(q\) is placed at a distance \(\frac{a}{2}\) directly above the centre of a square of side \(a\). The electric flux through the square (i.e. one face) is:
1. \(\frac{q}{\varepsilon_0}\)
2. \(\frac{q}{\pi\varepsilon_0}\)
3. \(\frac{q}{4\varepsilon_0}\)
4. \(\frac{q}{6\varepsilon_0}\)

Subtopic:  Gauss's Law |
 62%
From NCERT
PMT - 1997
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Two infinitely long parallel wires having linear charge densities λ1 and λ2 respectively are placed at a distance of R meters. The force per unit length on either wire will be K=14πε0

(1) K2λ1λ2R2

(2) K2λ1λ2R

(3) Kλ1λ2R2 

(4) Kλ1λ2R

Subtopic:  Electric Field |
 59%
From NCERT
PMT - 1998
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