The reagent that is used to remove ${\mathrm{SO}}_4^{2-}$ and Cl^- is -

1. NaOH             

2. Pb(NO₃)₂

3. BaSO₄             

4. KOH

A substance on treatment with dil. H₂SO₄ liberates a colourless gas which produces (i) turbidity with baryta water and (ii) turns acidified dichromate solution green. The reaction indicates the presence of:

(1) CO3^2-

(2) S^2-

(3) SO3^2-

(4) NO₂^-

The silver sulphate solution is used to separate:

1. nitrate and bromide

2. nitrate and chlorate

3. bromide and iodide

4. nitrate and nitrite

Find the method used for the preparation of soda extract.

1. Fusing sodium carbonate with the organic compound mixture, followed by extraction with water

2. Dissolving NaHCO₃ and the organic compound mixture in dilute HCl

3. Boiling Na₂CO₃ and the organic compound mixture with dilute HCl

4. Boiling Na₂CO₃ and a mixture of hydrocarbons in distilled water

The most stable carbocation among the following is:

1.		2.
3.		4.

The compound which forms one monochloro product when treated with chlorine is:

(1) n-pentane

(2) isopentane

(3) neo-pentane

(4) None of these

Among the following anions (a) CH₃, (b) NH₂, (c) OH^-, (d) F^-, the order of basicity is:

1. a > b > c > d

2. b > a > c > d

3. c > b > a > d

4. c > a > b > d

The electromeric effect in organic compounds is a :

1. Temporary effect

2. Permanent effect

3. Electromeric effect is only observed in inorganic molecules

4. None of the above

The arrangement in decreasing order of stability of $\stackrel{\bullet }{C}$H₃, $\stackrel{\bullet }{C_2}$H₅,(CH₃)₂$\stackrel{\bullet }{C}$H and (CH₃)₃ $\stackrel{\bullet }{C}$ free radicals is-

1. $\stackrel{\bullet }{C}$H₃ > $\stackrel{\bullet }{C_2}$H₅ > (CH₃)₂$\stackrel{\bullet }{C}$H > (CH₃)₃ $\stackrel{\bullet }{C}$  

2. (CH₃)₃ $\stackrel{\bullet }{C}$ > (CH₃)₂$\stackrel{\bullet }{C}$H > $\stackrel{\bullet }{C_2}$H₅ > $\stackrel{\bullet }{C}$H₃

3. $\stackrel{\bullet }{C_2}$H₅ > $\stackrel{\bullet }{C}$H₃ > (CH₃)₂$\stackrel{\bullet }{C}$H > (CH₃)₃ $\stackrel{\bullet }{C}$

4. (CH₃)₃ $\stackrel{\bullet }{C}$ > (CH₃)₂$\stackrel{\bullet }{C}$H >  $\stackrel{\bullet }{C}$H₃  >$\stackrel{\bullet }{{\mathrm{\hspace{0.17em}C}}_2}$H₅ 

H₂C = O behaves as:

1. Nucleophile

2. Electrophile

3. Both (1) and (2)

4. None of the above