Consider the two statements:
Assertion (A):
Iodine-KI reagent can be used to detect starch in a sample.
Reason (R):
Starch can hold iodine molecules in its helical portion and starch-iodine is blue in colour.
1.
Both (A) and (R) are True but (R) does not correctly explain(A).
2.
(A) is True but (R) is False.
3.
Both (A) and (R) are False.
4.
Both (A) and (R) are True and (R) correctly explains (A).
Subtopic: Â Carbohydrates: Starch & Glycogen |
 76%
Level 2: 60%+
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In the absence of an enzyme, the catalysed reaction:
| 1. | does not take place |
| 2. | takes place at a very slow rate |
| 3. | takes place at a higher rate |
| 4. | is not affected at all |
Subtopic: Â Enzymes |Â Enzyme Catalysis |
 85%
Level 1: 80%+
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Subtopic: Â Nucleic Acid |Â The DNA |
 83%
Level 1: 80%+
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Subtopic: Â Proteins |
 72%
Level 2: 60%+
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Prosthetic groups are distinguished from other cofactors in that they are:
1. tightly bound to the apoenzyme
2. inorganic compounds
3. metal ions
4. vitamins
1. tightly bound to the apoenzyme
2. inorganic compounds
3. metal ions
4. vitamins
Subtopic: Â Enzyme Cofactors |
 91%
Level 1: 80%+
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Consider the given two statements:
| Assertion (A): | Lipids come under acid insoluble fraction of the cell. |
| Reason (R): | Acid insoluble fraction is the macromolecular fraction and lipids are macromolecules. |
| 1. | (A) is True but (R) is False |
| 2. | Both (A) and (R) are True and (R) correctly explains (A) |
| 3. | Both (A) and (R) are True and but (R) does not correctly explain (A) |
| 4. | (A) is False but (R) is True |
Subtopic: Â Introduction |
 75%
Level 2: 60%+
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Concanavalin A is:
| 1. | a primary metabolite in living organism and an alkaloid |
| 2. | a primary metabolite in living organism and a lectin |
| 3. | a secondary metabolite in living organism and a lectin |
| 4. | a secondary metabolite in living organism and an alkaloid |
Subtopic: Â Primary & Secondary Metabolites |
 87%
Level 1: 80%+
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Cellulose does not form blue colour with iodine because
| 1. | It breaks down when iodine reacts with it. |
| 2. | It is a disaccharide. |
| 3. | It is a helical molecule. |
| 4. | It does not contain complex helices and hence cannot hold iodine molecules. |
Subtopic: Â Carbohydrates: Cellulose, Chitin, Inulin & Agar |
 87%
Level 1: 80%+
NEET - 2023
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Malonate inhibits the growth of pathogenic bacteria by inhibiting the activity of:
1. Dinitrogenase
2. Succinic dehydrogenase
3. Amylase
4. Lipase
1. Dinitrogenase
2. Succinic dehydrogenase
3. Amylase
4. Lipase
Subtopic: Â Enzyme Inhibition |
 90%
Level 1: 80%+
NEET - 2023
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Given below are two statements:
In the light of the above statements, choose the correct answer from the options given below:
1. Statement I is false but Statement II is true.
2. Both Statement I and Statement II are true.
3. Both Statement I and Statement II are false.
4. Statement I is true but Statement II is false.
| Statement I: | Low temperature preserves the enzyme in a temporarily inactive state whereas high temperature destroys enzymatic activity because proteins are denatured by heat. |
| Statement II: | When the inhibitor closely resembles the substrate in its molecular structure and inhibits the activity of the enzyme, it is known as competitive inhibitor. |
1. Statement I is false but Statement II is true.
2. Both Statement I and Statement II are true.
3. Both Statement I and Statement II are false.
4. Statement I is true but Statement II is false.
Subtopic: Â Factors Affecting Enzyme Catalysis Reaction |Â Enzyme Inhibition |
 88%
Level 1: 80%+
NEET - 2023
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