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Q. No.An electromagnetic wave is moving along negative \(z (-z)\) direction and at any instant of time, at a point, its electric field vector is \(3\hat j~\text{V/m}\). The corresponding magnetic field at that point and instant will be: (Take \(c=3\times10^{8}~\text{ms}^{-1}\))
1.
\(10\hat i~\text{nT}\)
2.
\(-10\hat i~\text{nT}\)
3.
\(\hat i~\text{nT}\)
4.
\(-\hat i~\text{nT}\)
Subtopic: Properties of EM Waves |
53%
From NCERT
NEET - 2022
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The magnetic field of a plane electromagnetic wave
is given by,
\(\vec B=3\times10^{-8}\text{cos}(1.6\times10^3x+48\times10^{10}t)\hat j~\text{T}.\)
The associated electric field will be:
is given by,
\(\vec B=3\times10^{-8}\text{cos}(1.6\times10^3x+48\times10^{10}t)\hat j~\text{T}.\)
The associated electric field will be:
| 1. | \(3 \times 10^{-8} \text{cos}\left(1.6 \times 10^3 x+48 \times 10^{10} t\right) \hat{i}~\text{ V/m}\) |
| 2. | \(3 \times 10^{-8} \text{sin} \left(1.6 \times 10^3 {x}+48 \times 10^{10} {t}\right) \hat{{i}}~ \text{V} / \text{m}\) |
| 3. | \(9 \text{sin} \left(1.6 \times 10^3 {x}-48 \times 10^{10} {t}\right) \hat{{k}} ~~\text{V} / \text{m}\) |
| 4. | \(9 \text{cos} \left(1.6 \times 10^3 {x}+48 \times 10^{10} {t}\right) \hat{{k}}~~\text{V} / \text{m}\) |
Subtopic: Properties of EM Waves |
56%
From NCERT
NEET - 2022
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The ratio of the magnitude of the magnetic field and electric field intensity of a plane electromagnetic wave in free space of permeability \(\mu_0\) and permittivity \(\varepsilon_0\) is:
(Given that \(c=\) velocity of light in free space)
1. \(c\)
2. \(\dfrac1c\)
3. \(\dfrac{c}{\sqrt{\mu_0\varepsilon_0}}\)
4. \(\dfrac{\sqrt{\mu_0\varepsilon_0}}{c}\)
(Given that \(c=\) velocity of light in free space)
1. \(c\)
2. \(\dfrac1c\)
3. \(\dfrac{c}{\sqrt{\mu_0\varepsilon_0}}\)
4. \(\dfrac{\sqrt{\mu_0\varepsilon_0}}{c}\)
Subtopic: Properties of EM Waves |
59%
From NCERT
NEET - 2022
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If \(\lambda_X,\lambda_I,\lambda_M\) and \(\lambda_\gamma\) are the wavelengths of \(X\)-rays, infrared rays, microwaves and \(\gamma\)-rays respectively, then:
| 1. | \(\lambda_\gamma<\lambda_X<\lambda_I<\lambda_M\) |
| 2. | \(\lambda_M<\lambda_I<\lambda_X<\lambda_\gamma\) |
| 3. | \(\lambda_X<\lambda_\gamma<\lambda_M<\lambda_I\) |
| 4. | \(\lambda_X<\lambda_I<\lambda_\gamma<\lambda_M\) |
Subtopic: Electromagnetic Spectrum |
82%
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NEET - 2022
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When light propagates through a material medium of relative permittivity, \(\varepsilon_{r}\) and relative permeability, \(\mu_{r}\) the velocity of light, \(v\) is given by:
(\(c\) = velocity of light in vacuum)
1. \(v=\dfrac{{c}}{\sqrt{\varepsilon_{r} \mu_{{r}}}}\)
2. \(v={c}\)
3. \(v=\sqrt{\dfrac{\mu_{{r}}}{\varepsilon_{{r}}}}\)
4. \(v=\sqrt{\dfrac{\varepsilon_{{r}}}{\mu_{{r}}}}\)
(\(c\) = velocity of light in vacuum)
1. \(v=\dfrac{{c}}{\sqrt{\varepsilon_{r} \mu_{{r}}}}\)
2. \(v={c}\)
3. \(v=\sqrt{\dfrac{\mu_{{r}}}{\varepsilon_{{r}}}}\)
4. \(v=\sqrt{\dfrac{\varepsilon_{{r}}}{\mu_{{r}}}}\)
Subtopic: Properties of EM Waves |
86%
From NCERT
NEET - 2022
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Match List - I with List - II.
Choose the correct answer from the options given below:
| List -I (Electromagnetic waves) | List - II (Wavelength) | ||
| (a) | AM radio waves | (i) | \(10^{-10}~\text{m}\) |
| (b) | Microwaves | (ii) | \(10^{2} ~\text{m}\) |
| (c) | Infrared radiation | (iii) | \(10^{-2} ~\text{m}\) |
| (d) | \(X\)-rays | (iv) | \(10^{-4} ~\text{m}\) |
Choose the correct answer from the options given below:
| (a) | (b) | (c) | (d) | |
| 1. | (ii) | (iii) | (iv) | (i) |
| 2. | (iv) | (iii) | (ii) | (i) |
| 3. | (iii) | (ii) | (i) | (iv) |
| 4. | (iii) | (iv) | (ii) | (i) |
Subtopic: Electromagnetic Spectrum |
72%
From NCERT
NEET - 2022
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In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of \(2.0\times 10^{10}~ \text{Hz}\) and amplitude \(48~\text{Vm}^{-1}\). Then the amplitude of the oscillating magnetic field is: (Speed of light in free space \(3\times 10^{8}~ \text{ms}^{-1}\))
1. \(1.6 \times 10^{-6} ~\text{T}\)
2. \(1.6 \times 10^{-9} ~\text{T}\)
3. \(1.6 \times 10^{-8} ~\text{T}\)
4. \(1.6 \times 10^{-7} ~\text{T}\)
1. \(1.6 \times 10^{-6} ~\text{T}\)
2. \(1.6 \times 10^{-9} ~\text{T}\)
3. \(1.6 \times 10^{-8} ~\text{T}\)
4. \(1.6 \times 10^{-7} ~\text{T}\)
Subtopic: Properties of EM Waves |
59%
From NCERT
NEET - 2023
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\(\varepsilon_0\) and \(\mu_0\) are the electric permittivity and magnetic permeability of free space respectively. If the corresponding quantities of a medium are \(2\varepsilon_0\) and \(1.5\mu_0\) respectively, the refractive index of the medium will nearly be:
1. \(\sqrt2\)
2. \(\sqrt3\)
3. \(3\)
4. \(2\)
1. \(\sqrt2\)
2. \(\sqrt3\)
3. \(3\)
4. \(2\)
Subtopic: Properties of EM Waves |
78%
From NCERT
NEET - 2023
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To produce an instantaneous displacement current of \(2~\text{mA}\) in the space between the parallel plates of a capacitor of capacitance \(4~\mu\text{F}\), the rate of change of applied variable potential difference \(\left(\frac{dV}{dt}\right)\) must be:
1. \( 800~ \text{V} / \text{s} \)
2. \( 500~ \text{V} / \text{s} \)
3. \( 200~ \text{V} / \text{s} \)
4. \( 400 ~\text{V} / \text{s}\)
1. \( 800~ \text{V} / \text{s} \)
2. \( 500~ \text{V} / \text{s} \)
3. \( 200~ \text{V} / \text{s} \)
4. \( 400 ~\text{V} / \text{s}\)
Subtopic: Displacement Current |
77%
From NCERT
NEET - 2023
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A capacitor of capacitance \(C\) is connected across an AC source of voltage \(V\), given by;
\(V=V_0 \sin \omega t\)
The displacement current between the plates of the capacitor would then be given by:
1. \( I_d=\frac{V_0}{\omega C} \sin \omega t \)
2. \( I_d=V_0 \omega C \sin \omega t \)
3. \( I_d=V_0 \omega C \cos \omega t \)
4. \( I_d=\frac{V_0}{\omega C} \cos \omega t\)
Subtopic: Displacement Current |
56%
From NCERT
NEET - 2021
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