The electronic configuration of a transition element X in +3 Oxidation state is [Ar]3d5.
The atomic number of X is :
1. 25
2. 26
3. 27
4. 24
Magnetic moment of K3[Fe(CN)5(H2O)] is
1. 0
2. 4.92
3. 3.87
4. 2.83
In the dichromate ion Cr2O72-,
1. 4 Cr-O bonds are equivalent
2. 6 Cr-O bonds are equivalent
3. All Cr-O bonds are equivalent
4. None of Cr-O bonds are equivalent
The main reason for a larger number of oxidation states exhibited by the actinoids than the corresponding lanthanoids is
1. The lesser energy difference between 5f and 6d orbitals than 4f and 5d orbitals
2. Larger atomic size of actinoids than the lanthanoids
3. More energy difference between 5f and 6d orbitals than between 4f and 5d orbitals
4. Greater reactive nature of the actinoids than the lanthanoids
HgCl2 and I2 both when dissolved in water containing I- ions the pair of species formed is
(a) HgI2, (b) HgI2, I-
(c) (d) Hg2I2, I-
The incorrect statement regarding the lanthanons is ;
1. | Europium shows +2 oxidation state |
2. | The basicity decreases as the ionic radius decreases from Pr to Lu |
3. | All the lanthanons are much more reactive than aluminium |
4. | Ce (+4) solutions are widely used as oxidising agents in volumetric analysis |
The correct electronic configuration of Gadolinium(Atomic number = 64) is :
1. [Xe]4f86d2
2. [Xe]4f95s1
3. [Xe]4f75d16s2
4. [Xe]4f65d26s2
Assuming complete ionisation, same moles of which of the following compounds will
require the least amount of acidified KMnO4 for complete oxidation?
1. FeSO4
2. FeSO3
3. FeC2O4
4. Fe(NO2)2
The reason for lanthanoid contraction is:
1. Negligible screening effect of 'f' orbitals
2. Increasing nuclear charge
3. Decreasing nuclear charge
4. Decreasing screening effect
A diamagnetic lanthanoid ion among the following is :
(At. numbers: Ce = 58, Sm = 62, Eu = 63, Yb = 70)
1. Ce2+
2. Eu2+
3. Sm2+
4. Yb2+