Henry’s law constant for the solution of methane in benzene at 298 K is 4.27 × 105 mm Hg. The mole fraction of methane in benzene at 298 K under 760 mm Hg will be:
1. 1.85 × 10–5
2. 192 × 10–4
3. 178 × 10–5
4. 18.7 × 10–5
The solubility of gases in liquids generally decreases as temperature increases.
The primary reason for this behavior is:
| 1. | Dissolution of a gas in a liquid is an endothermic process. |
| 2. | Dissolution of a gas in a liquid is an exothermic process. |
| 3. | Gases are highly compressible. |
| 4. |
All of the above statements are correct. |
Which law is applied when deep-sea divers use a breathing mixture of oxygen and less soluble helium to minimise the painful effects caused by the increased dissolution of gases in blood at high pressure?
| 1. | Raoult's law | 2. | Henry's law |
| 3. | Ideal gas Equation | 4. | All of the above |
| Type of solution | Example | ||
| a. | Solid in gas | i. | Aerated water |
| b. | Gas in liquid | ii. | Smoke |
| c. | Liquid in solid | iii. | Solution of hydrogen in palladium |
| d. | Gas in solid | iv. | Amalgams |
| a | b | c | d | |
| 1. | i | iii | iv | ii |
| 2. | ii | i | iv | iii |
| 3. | iii | i | iv | ii |
| 4. | iv | i | ii | iii |
Which graph represents the positive deviation of vapor pressure?
| 1. | 2. | ||
| 3. | 4. | None of the above |
The following solutions were prepared by dissolving 10 g of glucose (C6H12O6) in 250 ml of water (P1), 10 g of urea (CH4N2O) in 250 ml of water (P2) and 10 g of sucrose (C12H22O11) in 250 ml of water (P3). The decreasing order of osmotic pressures of these solutions is:
| 1. | P2 > P3 > P1 | 2. | P3 > P1 > P2 |
| 3. | P2 > P1 > P3 | 4. | P1 > P2 > P3 |
The correct option for the value of vapour pressure of a solution at 45 C with benzene to octane in a molar ratio 3:2 is:
[At 45 C vapour pressure of benzene is 280 mm Hg and that of octane is 420 mm Hg. Assume Ideal gas]
| 1. | 336 mm of Hg | 2. | 350 mm of Hg |
| 3. | 160 mm of Hg | 4. | 168 mm of Hg |
At room temperature, a dilute solution of urea is prepared by dissolving 0.60 g of urea in 360 g of water. If the vapour pressure of pure water at this temperature is 35 mm Hg, then calculate the lowering of vapour pressure:
(Given: Molar mass of urea = 60 g mol–1)
| 1. | 0.031 mmHg | 2. | 0.017 mmHg |
| 3. | 0.028 mmHg | 4. | 0.027 mmHg |
The mole fraction of glucose (C6H12O6) in an aqueous binary solution is 0.1. The mass percentage of water in it to the nearest integer is:
| 1. | 44% | 2. | 49 % |
| 3. | 47 % | 4. | 41 % |
The type of inter-molecular interactions present in:
| (a) | n-Hexane and n-octane | (i) | Van der Waal’s forces of attraction |
| (b) | NaClO4 and water | (ii) | Ion-dipole interaction |
| (iii) | Dipole-dipole interaction |
| (a) | (b) | |
| 1. | (i) | (ii) |
| 2. | (ii) | (ii) |
| 3. | (i) | (iii) |
| 4. | (iii) | (iii) |