Beans get cooked earlier in a pressure cooker, because:

1. The boiling point increases with increasing pressure
2. The boiling point decreases with increasing pressure
3. The extra pressure of the pressure cooker softens the beans
4. Internal energy is not lost while cooking in a pressure cooker

Subtopic:  Introduction & Colligative properties |
 54%
From NCERT
AIPMT - 2001
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If 22 g of benzene is dissolved in 122 g of carbon tetrachloride then the mass percentage of carbon tetrachloride (CCl4) is-

1. 82.72%

2. 83.72%

3. 84.72%

4. 85.72%

Subtopic:  Introduction & Colligative properties |
 68%
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The partial pressure of ethane over a solution containing 6.56 × 10–2 g of ethane is 1 bar. If the solution contains 5.00 × 10–2 g of ethane, the partial pressure of the gas will be -

1. 0.66 bar

2. 0.96 bar

3. 0.76 bar

4. 0.19 bar

Subtopic:  Concentration Terms & Henry's Law |
 70%
From NCERT
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The positive deviations from Raoult’s law mean the vapour pressure is:

1. Higher than expected.
2. Lower than expected.
3. As expected.
4. None of the above

Subtopic:  Raoult's Law |
 85%
From NCERT
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The vapour pressure of 1 molal solution of a non-volatile solute in water at 300 K would be -

(The vapour pressure of water at 300 K = 12.3 kPa)

1. 21.08 kPa 2. 12.08 kPa
3. 33.08 kPa 4. 4.08 kPa
Subtopic:  Relative Lowering of Vapour Pressure |
 74%
From NCERT
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A solution containing 30 g of non-volatile solute in 90 g of water has a vapour pressure of 2.8 kPa at 298 K. Further, 18 g of water is then added to the solution and the new vapour pressure becomes 2.9 kPa at 298 K.

The molar mass of the solute will be -

1.  23 g mol−1

2.  34 g mol−1

3.  15 g mol−1

4.  46 g mol−1

Subtopic:  Relative Lowering of Vapour Pressure |
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Two elements A and B form compounds having formula AB2 and AB4. When dissolved in 20 g of benzene (C6H6), 1 g of AB2 lowers the freezing point by 2.3 K whereas 1.0 g of AB4 lowers it by 1.3 K. The atomic masses of A and B are respectively -

(Kf for benzene is 5.1 K kg mol-1)

1. 15.59 u and 52.64 u

2. 25.59 u and 42.64 u

3. 13.59 u and 52.64 u

4. 23.59 u and 32.64 u

Subtopic:  Depression of Freezing Point |
 61%
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The type of inter molecular interactions present in

(a) n-hexane and n-octane (i) Van der Waal’s forces of attraction
(b) NaClO4 and water (ii) ion-dipole interaction
(iii) dipole-dipole interaction
 
(a) (b)
1. (i) (ii)
2. (ii) (ii)
3. (i) (iii)
4. (iii) (iii)
Subtopic:  Azeotrope |
 64%
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The insoluble compound in water is /are

1. Phenol

2. Formic acid and toluene

3. Phenol and toluene 

4. Toluene and chloroform

Subtopic:  Introduction & Colligative properties |
 58%
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If the solubility product of CuS is 6 × 10–16, the maximum molarity of CuS in an aqueous solution will be

1. 1.45 × 10−8 mol L−1 2. 3.45 × 10−8 mol L−1
3. 2.45 × 10−8 mol L−1 4. 4.25 × 10−8 mol L−1
Subtopic:  Concentration Terms & Henry's Law |
 66%
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