x gram of pure As2S3 is completely oxidised to respective highest oxidation states by 50 ml of 0.1 M hot acidified KMnO4 then x mass of As2S3 taken is : (Molar mass of As2S3 = 246)
1. 22.4 g
2. 43.92 g
3. 64.23 g
4. None
In the reaction Na2S2O3 + 4Cl2 + 5H2O → Na2SO4 + H2SO4 + 8HCI the equivalent weight of Na2S2O3 will be
1. M/4
2. M/8
3. M/1
4. M/2
(M= molecular weight of Na2S2O3)
In the reaction CrO5 + H2SO4 → Cr2(SO4)3 + H2O + O2 one mole of CrO5 will liberate how many moles of O2
1. 5/2
2. 5/4
3. 9/2
4. none of these
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0.4g of a polybasic acid HnA (all the hydrogens are acidic) requires 0.5g of NaOH for complete neutralization. The number of replaceable hydrogen atoms in the acid and the molecular weight of 'A' would be : (Molecular weight of the acid is 96 gms.)
1. 1, 95
2. 2, 94
3. 3, 93
4. 4, 92
Number of moles of MnO-4 required to oxidise one mole of ferrous oxalate completely in acidic medium will be
1. 0.6 mole
2. 0.4 mole
3. 7.5 moles
4. 0.2 mole
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One mole of N2H4 loses 10 mole of electrons to form a new compound Y. Assuming that all nitrogen appear in the new compound, what is the oxidation state of N2 in Y ? (There is no change in the oxidation state of hydrogen)
1. + 3
2. – 3
3. – 1
4. + 5
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Consider the change in the oxidation state of Bromine corresponding to different emf values as shown in the diagram below:
\(\small{BrO_4^-\ \overset{1.82V}{\longrightarrow}\ BrO_3^-\ \overset{1.5V}{\longrightarrow} HBrO\ \overset{1.595V}{\longrightarrow}\ Br_2 \overset{1.0652V}{\longrightarrow}\ Br^-}\)
Then the species undergoing disproportionation is:-
1.
2.
3.
4. HBrO
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Iron does not get oxidised in:
1. | Rusting of iron sheets |
2. | Decolourisation of blue CuSO4 solution by iron |
3. | Formation of Fe(CO)5 from Fe |
4. | Liberation of H2 from steam by iron at a high temperature |
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1. Y > X > Z
2. Z > X > Y
3. X > Y > Z
4. Y > Z > X
The respective oxidation states of P in H4P2O5, H4P2O6, and H4P2O7 are:
1. | +3, +5, and +4 | 2. | +5, +3, and +4 |
3. | +5, +4, and +3 | 4. | +3, +4, and +5 |
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