In Young's double slit experiment with slit seperation d, a monochromatic light of wavelength $\mathrm{\lambda }$ is used. The angular seperation of the fringes is

1. $\mathrm{d}/\mathrm{\lambda }$

2. $\mathrm{\lambda }/\mathrm{d}$

3. $2\mathrm{\lambda }/\mathrm{d}$

4. $\mathrm{\lambda }/2\mathrm{d}$

Two slits in Young's experiment have widths in the ratio 1:25. The ratio of intensity at the maximum and minimum in the interferance pattern, $\frac{{\mathrm{I}}_{\max }}{{\mathrm{I}}_{\min }}$is

1. $\frac{121}{49}$

2. $\frac{49}{121}$

3. $\frac{4}{9}$

4. $\frac{9}{4}$

At the first minimum adjacent to the central maximum of a single-slit differaction pattern, the phase difference between the Huygen's wavelet from the edge of the slit and the wavelet from the midpoint of the slit is

1. $\frac{\mathrm{\pi }}{2}$radian 

2. $\mathrm{\pi } \mathrm{radian}$

3. $\frac{\mathrm{\pi }}{8}$ radian

4. $\frac{\mathrm{\pi }}{4}$radian

Two beams of light will not give rise to an interference pattem, if

1. They are coherent

2. They have the same wavelength

3. They are linearly polarized perpendicular to each other

4. They are not monochromatic

Young's experiment is performed in air and then performed in water, the fringe width 

1. Will remain same

2. Will decrease

3. Will increase

4. Will be infinite

In the Young's double slit experiment, if the phase difference between the two waves interfering at a point is $\mathrm{\varphi }$, the intensity at that point can be expressed by the expression

1. $\mathrm{l}=\sqrt{{\mathrm{A}}^2+{\mathrm{B}}^2 {\cos }^2\mathrm{\varphi }}$

2. $\mathrm{I}=\frac{\mathrm{A}}{\mathrm{B}}\mathrm{cos\varphi }$

3. $\mathrm{I}=\mathrm{A}+\mathrm{B} \cos \frac{\mathrm{\varphi }}{2}$

4. $\mathrm{I}=\mathrm{A}+\mathrm{B} \mathrm{cos\varphi }$

Where A and B depend upon the amplitude of the two waves.

A slit of width a is illuminated by white light. For red light $\left(\mathrm{\lambda }=6500\stackrel{°}{\mathrm{A}}\right)$, the first minima is obtained at $\mathrm{\theta }=30°$. Then the value of a will be 

1. $3250 \stackrel{°}{\mathrm{A}}$

2. $6.5\times {10}^{-4} \mathrm{mm}$

3. 1.24 microns

4. $2.6\times {10}^{-4} \mathrm{cm}$

Two waves originating from source S₁ and S₂ having zero phase difference and common wavelength $\lambda$ will show completely destructive interference at a point P if $\left({\mathrm{S}}_1\mathrm{P}-{\mathrm{S}}_2\mathrm{P}\right)$ is

1. 5$\lambda$

2. 3$\lambda$ / 4

3. 2$\lambda$

4. 11$\lambda$ / 2

The Brewster angle for the glass-air interface is 54.74^o. lf a ray of light going from air to glass strikes at an angle of incidence 45^o, then the angle of refraction is

(Hint: tan 54.74^o = $\sqrt{2}$)

1. 60^o

2. 30^o

3. 25^o

4. 54.74^o

The path difference between two interfering waves at a point on the screen is $\lambda /6.$ The ratio of intensity at this point and that at the central bright fringe will be (Assume that intensity due to each slit in same)

1. 0.853

2. 8.53

3. 0.75

4. 7.5