A body executes simple harmonic motion. The potential energy (P.E.), the kinetic energy (K.E.) and total energy (T.E.) are measured as a function of displacement x. Which of the following statements is true ?

(1)  P.E. is maximum when x = 0

(2)  K.E. is maximum when x = 0

(3)  T.E. is zero when x = 0

(4)  K.E. is maximum when x is maximum

Subtopic:  Energy of SHM |
 89%
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­­A man measures the period of a simple pendulum inside a stationary lift and finds it to be T sec. If the lift accelerates upwards with an acceleration g4 , then the period of the pendulum will be

(1) T

(2) T4

(3) 2T5

(4) 2T5

Subtopic:  Angular SHM |
 85%
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The total energy of a particle, executing simple harmonic motion is:

1.  x                 

2.  x2

3.  Independent of x 

4.   x1/2

Subtopic:  Energy of SHM |
 74%
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A simple pendulum is suspended from the roof of a trolley which moves in a horizontal direction with an acceleration a, then the time period is given by T=2πlg',  where g'   is equal to

(1) g                                                       

(2) g-a

(3) g+a

(4) g2+a2

Subtopic:  Angular SHM |
 88%
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If the length of second's pendulum is decreased by 2%, how many seconds it will lose per day?

1. 3927 sec

2. 3727 sec

3. 3427 sec

4. 864 sec

Subtopic:  Simple Harmonic Motion |
 68%
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In a simple pendulum, the period of oscillation T is related to length of the pendulum l as

(1) lT=constant

(2) l2T=constant

(3) lT2=constant

(4) l2T2=constant

Subtopic:  Angular SHM |
 83%
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The equation of motion of a particle is \({d^2y \over dt^2}+Ky=0 \) where \(K\) is a positive constant. The time period of the motion is given by: 

1. \(2 \pi \over K\) 2. \(2 \pi K\)
3. \(2 \pi \over \sqrt{K}\) 4. \(2 \pi \sqrt{K}\)
Subtopic:  Simple Harmonic Motion |
 75%
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The kinetic energy of a particle executing SHM is 16 J when it is in its mean position. If the amplitude of oscillations is 25 cm and the mass of the particle is 5.12 kg, the time period of its oscillation will be:
1. π5sec 
2. 2π sec
3. 20π sec   
4. 5π sec

Subtopic:  Energy of SHM |
 70%
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A pendulum has time period T. If it is taken on to another planet having acceleration due to gravity half and mass 9 times that of the earth then its time period on the other planet will be

(1) T

(2) T

(3) T1/3

(4) 2T

Subtopic:  Angular SHM |
 85%
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A particle in SHM is described by the displacement equation xt=Acos ωt+θ. If the initial position of the particle is 1 cm and its initial velocity is πcm/s, what is its amplitude? (The angular frequency of the particle is π s-1)

(1)  1 cm       

(2)  2 cm

(3)  2 cm     

(4)  2.5 cm

Subtopic:  Simple Harmonic Motion |
 62%
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