A mass 1 kg suspended from a spring whose force constant is $400 {\mathrm{Nm}}^{-1}$, executes simple harmonic oscillation. When the total energy of the oscillator is 2 J, the maximum acceleration experienced by the mass will be:

1. $2 {\mathrm{ms}}^{-2}$

2. $4 {\mathrm{ms}}^{-2}$

3. $40 {\mathrm{ms}}^{-2}$

4. $400 {\mathrm{ms}}^{-2}$

What will be the force constant of the spring system shown in the figure?

1. $\frac{k_1}{2}+k_2$

2. ${\left[\frac{1}{2k_1}+\frac{1}{k_2}\right]}^{-1}$

3. $\frac{1}{2k_1}+\frac{1}{k_2}$

4. ${\left[\frac{2}{k_1}+\frac{1}{k_2}\right]}^{-1}$

One end of a spring of force constant \(k\) is fixed to a vertical wall and the other to a block of mass \(m\) resting on a smooth horizontal surface. There is another wall at a distance \(x_0\) from the block. The spring is then compressed by \(2x_0\) and then released. The time taken to strike the wall will be?

A piece of wood had dimensions a, b and c. Its relative density is d. It is floating in water such that the side c is vertical. It is now pushed down gently and released. The time period is:

1. $T=2\mathrm{\pi }\sqrt{\left(\frac{\mathrm{abc}}{\mathrm{g}}\right)}$

2. $T=2\mathrm{\pi }\sqrt{\left(\frac{\mathrm{ba}}{\mathrm{dg}}\right)}$

3. $T=2\mathrm{\pi }\sqrt{\left(\frac{\mathrm{g}}{\mathrm{dc}}\right)}$

4. $T=2\mathrm{\pi }\sqrt{\left(\frac{\mathrm{dc}}{\mathrm{g}}\right)}$

Which of the following figure represent(s) damped simple harmonic motions?

1. 

2. 

3. 

4. 

The amplitude of the damped oscillator becomes (1/3) in 2s. Its amplitude after 6s is 1/n times the original. Then n is equal to:

1. $2^3$

2. $3^2$

3. $3^{1/3}$

4. $3^3$

The distance covered by a particle undergoing SHM in one time period is: (amplitude = A)
1. zero
2. A
3. 2 A
4. 4 A

An object suspended from a spring exhibits oscillations of period T. Now, the spring is cut in two halves and the same object is suspended with two halves as shown in the figure. The new time period of oscillation will become :

1. $\frac{\mathrm{T}}{2\sqrt{2}}$

2. $\frac{T}{2}$

3. $\frac{T}{\sqrt{2}}$

4. 2T

A weightless spring that has a force constant k oscillates with frequency n when a mass m is suspended from it. The spring is cut into equal halves and a mass 2m is suspended from one part of the spring. The frequency of oscillation will now become:

1. n

2. 2n

3. $\frac{\mathrm{n}}{\sqrt{2}}$

4. $\mathrm{n}{\left(2\right)}^{1/2}$

Two springs of force constants k and 2k are connected to a mass m as shown below. The frequency of oscillation of the mass is:

(1) $\frac{1}{2\mathrm{\pi }}\sqrt{k/m}$

(2) $\frac{1}{2\mathrm{\pi }}\sqrt{2k/m}$

(3) $\frac{1}{2\mathrm{\pi }}\sqrt{\frac{3k}{m}}$

(4) $\frac{1}{2\mathrm{\pi }}\sqrt{\frac{m}{k}}$