The figure shows the circular motion of a particle which is at the topmost point on the y-axis at t=0. The radius of the circle is B and the sense of revolution is clockwise.  The time period is indicated in the figure. The simple harmonic motion of the x-projection of the radius vector of the rotating particle P is:
                   

(1) x(t) = Bsin 2πt30

(2) x(t) = Bcos πt15

(3) x(t) = Bsin πt15+π2

(4) x(t) = Bcosπt15+π2

Subtopic:  Phasor Diagram |
 53%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

1.00×10-20 kg particle is vibrating with simple harmonic motion with a period of 1.00×10-5 s and a maximum speed of 1.00×103 m/s. The maximum displacement of the particle from the mean position is:

(1) 1.59 mm

(2) 1.00 cm

(3) 10 m

(4) None of these

Subtopic:  Simple Harmonic Motion |
 73%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

Which one of the following equations does not represent SHM, x = displacement, and t = time? Parameters a, b and c are the constants of motion.

(1) x = a sin bt

(2) x = a cos bt + c

(3) x = a sin bt + c cos bt

(4) x = a sec bt + c cosec bt

Subtopic:  Types of Motion |
 74%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

advertisementadvertisement

The bob of a simple pendulum of length L is released at time t = 0 from a position of small angular displacement. Its linear displacement at time t is given by :

(1) X=a sin2πLg×t

(2) X=a cos2πgL×t

(3) X=a singL×t

(4) X=a cosgL×t

Subtopic:  Simple Harmonic Motion |
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

A particle in SHM is described by the displacement function x(t)=A cos(ωt+ϕ), ω=2π/T. If the initial (t = 0) position of the particle is 1 cm, its initial velocity is π cm s-1 and its angular frequency is πs-1, then the amplitude of its motion is:

(1) π cm

(2) 2 cm

(3) 2 cm

(4) 1 cm

Subtopic:  Simple Harmonic Motion |
 59%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

A particle starts SHM from the mean position. Its amplitude is 'a' and total energy E. At one instant its kinetic energy is 3E/4. Its displacement at this instant is :

(1) y=a/2

(2) y=a2

(3) y=a3/2

(4) y = a

Subtopic:  Energy of SHM |
 73%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

advertisementadvertisement

A particle is vibrating in a simple harmonic motion with an amplitude of 4 cm. At what displacement from the equilibrium position, is its energy half potential and half kinetic?

(1) 1 cm

(2) 2 cm

(3) 3 cm

(4) 22 cm

Subtopic:  Energy of SHM |
 79%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

A body of mass 500 g is attached to a horizontal spring of spring constant 8 π2Nm-1. If the body is pulled to a distance of 10 cm from its mean position, then its frequency of oscillation is :

(1) 2 Hz

(2) 4 Hz

(3) 8 Hz

(4) 0.5 Hz

Subtopic:  Simple Harmonic Motion |
 71%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

Two springs of force constants k and 2k are connected to a mass m as shown below. The frequency of oscillation of the mass is:

(1) 12πk/m

(2) 12π2k/m

(3) 12π3km

(4) 12πmk

Subtopic:  Combination of Springs |
 86%
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints

advertisementadvertisement

A weightless spring that has a force constant k oscillates with frequency n when a mass m is suspended from it. The spring is cut into equal halves and a mass 2m is suspended from one part of the spring. The frequency of oscillation will now become:

1. n

2. 2n

3. n2

4. n(2)1/2

Subtopic:  Simple Harmonic Motion |
 65%
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints