In the given reaction,

$\stackrel{\mathrm{Br}}{\stackrel{|}{{\mathrm{CH}}_2}}-CH=C{H}_2\stackrel{NaN{H}_2/∆}{\to }\left[X\right]$

[X] will be:

(1) $C{H}_3-C\equiv CH$

(2) $H_{2}C=C\equiv C{H}_2$

(3) $C{H}_3-C\equiv \stackrel{⊝}{C}\stackrel{\oplus }{N}a$

(4) $H_{2}C=C\equiv \stackrel{⊝}{C}H\stackrel{\oplus }{N}a$

Consider the following statements :

(i) Pyrolytic elimination is always  syn elimination.

(ii) In pyrolytic elimination, product formation takes place by most stable eclipsed conformation.

(iii) In pyrolytic elimination, product formation takes place by Hofmann rule.

(iv) In pyrrolytic elimination, product formation takes place by Saytzeff rule.

Of these statements :

(1) (i), (ii) and (iv) are correct

(2) (i), (ii) and (iii) are correct

(3) (i) and (ii) are correct

(4) (ii) and (iii) are correct

Dichloromethane on treatment with alc. KOH/$∆$ gives:

(1) Carbene

(2) Diclorocarbene

(3) Singlet chlorocarbene

(4) Triplet chlorocarbene

Arrange the reactivity of alcohols in decreasing order for E1 elimination reaction:

(i) $OH$
$l$
$C{H}_3-CH-C{H}_3$

(ii) $OH$
$l$
$C{H}_3-C-C{H}_3$
$l$
$C{H}_3$

(iii) $OH$
$l$
$C_6{H}_5-C-C{H}_3$
$l$
$C{H}_3$

(iv) $C{H}_3-C{H}_2-C{H}_{2}OH$

Select the correct answer from the codes given below:

Codes:

1. (iii), (ii), (iv), (i)

2. (ii), (iii), (iv), (i)

3. (ii), (iii), (i), (iv)

4. (iii), (ii), (i), (iv)

Which one of the following pairs is correctly matched?

(1)  E1cb reaction, Hofmann elimination

(2) Hofmann rule, most substituted alkene

(3) Saytzeff rule, least substituted alkene

(4) E1 reaction, Hofmann elimination

Which one of the following is correctly matched?

1.		E2 reaction
2.		E2 reaction
3.	CH3CH2CH2OH	E1 reaction
4.		E1cb reaction

In the given reaction:

${\mathrm{CH}}_3-{\mathrm{CH}}_2-\underset{{\mathrm{CH}}_3}{\underset{|}{\mathrm{CH}}}-{\mathrm{CH}}_2-\mathrm{Br}\stackrel{\mathrm{alc}.\mathrm{KOH}/∆}{\to }\left[\mathrm{X}\right]$

[X] will be:

(1) $C{H}_3-C{H}_2-C=C{H}_2$
$I$
$C{H}_3$

(2) $C{H}_3-CH=C-C{H}_3$
$l$
$C{H}_3$

(3) $C{H}_2=CH-CH-C{H}_3$
$l$
$C{H}_3$

(4) $C{H}_3-CH=CH-C{H}_2-C{H}_3$

Reaction intermediate of E1cb reaction is:

1. Carbocation

2. Carbanion

3. benzyne

4. free radical

Reaction intermediate of E1 reaction is:

(1) Carbocation

(2) carbanion

(3) Carbene

(4) free radical

Which compound will give E1cb reaction?

(1) $C{F}_3-CHC{l}_2$

(2) $C_6{H}_5-C{H}_2-C{H}_2-F$

(3) $N{O}_2$
$l$
$C{H}_3-CH-CH{C}_6{H}_5$
$l$
$OCOC{H}_3$

(4) All of these