The breaking stress of a wire depends upon:

A steel cable with a radius of 1.5 cm supports a chairlift at a ski area. If the maximum stress is not to exceed 10⁸ N/m², what is the maximum load that the cable can support?
1. 7.06 x 10⁴ N
2. 5.03 x 10⁴ N
3. 1.09 x 10⁴ N
4. 17 x 10⁴ N

The breaking stress of a wire going over a smooth pulley in the following question is \(2\times 10^{9}\) N/${\mathrm{m}}^2$. What would be the minimum radius of the wire used if it is not to break?

A light rod of length \(2~\text{m}\) is suspended from the ceiling horizontally by means of two vertical wires of equal length. A weight \(W\) is hung from the light rod as shown in the figure. The rod is hung by means of a steel wire of cross-sectional area \(A_1 = 0.1~\text{cm}^2\) and brass wire of cross-sectional area\(A_2 = 0.2~\text{cm}^2\). To have equal stress in both wires, \(\frac{T_1}{T_2}?\)${\mathrm{}}_{}$

To break a wire, a force of \(10^6~\text{N/m}^{2}\) is required. If the density of the material is \(3\times 10^{3}~\text{kg/m}^3,\) then the length of the wire which will break by its own weight will be:
1. \(34\) m
2. \(30\) m
3. \(300\) m
4. \(3\) m

A uniform wire of length \(3\) m and mass \(10\) kg is suspended vertically from one end and loaded at another end by a block of mass \(10\) kg. The radius of the cross-section of the wire is \(0.1\) m. The stress in the middle of the wire is: (Take \(g=10\) ms^-2)

lf \(\rho\) is the density of the material of a wire and \(\sigma\) is the breaking stress, the greatest length of the wire that can hang freely without breaking is:
1. \(\frac{2}{\rho g}\)
2. \(\frac{\rho}{\sigma g}\)
3. \(\frac{\rho g}{2 \sigma}\)
4. \(\frac{\sigma}{\rho g}\)

One end of a uniform wire of length \(L\) and of weight \(W\) is attached rigidly to a point in the roof and a weight \(W_1\) is suspended from its lower end. If \(A\) is the area of cross-section of the wire, the stress in the wire at a height \(\frac{3L}{4}\) from its lower end is:
1. \(\frac{W+W_1}{A}\)
2. \(\frac{4W+W_1}{3A}\)
3. \(\frac{3W+W_1}{4A}\)
4. \(\frac{\frac{3}{4}W+W_1}{A}\)

A wire can sustain a weight of 10 kg before breaking. If the wire is cut into two equal parts, then each part can sustain a weight of:

The length of an elastic string is \(a\) metre when the longitudinal tension is \(4\) N and \(b\) metre when the longitudinal tension is \(5\) N. The length of the string in metre when the longitudinal tension is \(9\) N will be: