The PV diagram of an ideal gas is shown in the figure. The work done by the gas in the process is given by:
1. | \(\frac{9}{2}P_0V_0\) | 2. | \(\frac{15}{2}P_0V_0\) |
3. | \(\frac{13}{2}P_0V_0\) | 4. | \(\frac{3}{2}P_0V_0\) |
A pressure (P) versus volume (V) graph is obtained for an ideal gas from state A to State B (as shown in the figure below). Which of the following is the correct statement?
1. | The temperature of gas increases continuously. |
2. | The temperature of gas decreases continuously. |
3. | The temperature first increases, then decreases. |
4. | The temperature first decreases, then increases |
When the sink temperature is kept at 400 K, the efficiency of a Carnot engine is 50%. While keeping the source temperature constant, by how much should we reduce the sink temperature to increase the efficiency to 60%?
1. | 80 K | 2. | 70 K |
3. | 320 K | 4. | 240 K |
Which of the following graph shows the variation of pressure P with volume V for an ideal gas at a constant temperature?
1. | 2. | ||
3. | 4. |
A gas performs the minimum work when it expands:
1. | Isochorically | 2. | Isobarically |
3. | Adiabatically | 4. | Isothermally |
An ideal gas goes from A to B via two processes, l and ll, as shown. If and are the changes in internal energies in processes I and II, respectively, then (\(P:\) pressure, \(V:\) volume)
1. | ∆U1 > ∆U2 | 2. | ∆U1 < ∆U2 |
3. | ∆U1 = ∆U2 | 4. | ∆U1 ≤ ∆U2 |
An ideal monoatomic gas \(\left(\gamma = \frac{5}{3}\right )\) absorbs 50 cal in an isochoric process. The increase in internal energy of the gas is:
1. | 20 cal | 2. | Zero |
3. | 50 cal | 4. | 30 cal |
The pressure-temperature (P-T) graph for two processes, A and B, in a system is shown in the figure. If and are work done by the gas in process A and B respectively, then:
1. | \(W_{1}\) = \(W_{2}\) | 2. | \(W_{1}\) < \(W_{2}\) |
3. | \(W_{1}\) > \(W_{2}\) | 4. | \(W_{1}\) = \(-W_{2}\) |
The variation of molar heat capacity at constant volume with temperature T for a monatomic gas is:
1. | 2. | ||
3. | 4. |
When a system is moved from state a to state b along the path acb, it is discovered that the system absorbs 200 J of heat and performs 80 J of work. Along the path adb, heat absorbed Q = 144 J. The work done along the path adb is:
1. | 6 J | 2. | 12 J |
3. | 18 J | 4. | 24 J |