Q. No.What is F2 phenotypic ratio in a dihybrid cross?
1.
1 : 1
2.
3 : 1
3.
9 : 3 : 3 : 1
4.
1 : 1 : 1: 1
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In cases of Phenylketonuria:
| 1. | The affected individual lacks an enzyme that converts the amino acid tyrosine into phenylalanine. |
| 2. | The affected individual makes an enzyme that converts the amino acid tyrosine into phenylalanine. |
| 3. | The affected individual makes an enzyme that converts the amino acid phenylalanine into tyrosine. |
| 4. | The affected individual lacks an enzyme that converts the amino acid phenylalanine into tyrosine. |
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In sickle cell anaemia, the mutant haemoglobin molecule undergoes:
| 1. | Polymerisation under low oxygen tension causing changes in the shape of the RBC to a sickle-like structure |
| 2. | Depolymerisation under low oxygen tension causing that changes the shape of the RBC to a sickle-like structure |
| 3. | Denaturation under high oxygen tension causing changes in the shape of the RBC to a sickle-like structure |
| 4. | Denaturation |
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T. H. Morgan worked on the fruit fly, Drosophila melanogaster. Which of the following is not an advantage of this fly?
| 1. | They could be grown on a simple synthetic medium in the laboratory. |
| 2. | They complete their life cycle in about two years, and a single mating could produce a large number of progeny flies. |
| 3. | There was a clear differentiation of the sexes – the male and female flies are easily distinguishable. |
| 4. | It has many types of hereditary variations that can be seen with low-power microscopes. |
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In true breeding, the allelic pair of genes are:
| 1. | Homologous | 2. | Linked |
| 3. | Stable | 4. | Homozygous |
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What proportion of progeny in F2 generation in a Mendel monohybrid cross resembled the parent [of P generation] that expressed the recessive trait?
| 1. | ¼ | 2. | ½ |
| 3. | ¾ | 4. | 2/3 |
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During his observation of spermatogenesis in a few insects, Henking found that a nuclear structure was received by 50 % of the sperms. He called this structure as:
| 1. | X – body | 2. | Y–body |
| 3. | X – chromosome | 4. | Y – chromosome |
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The expression of only one of the parental characters in a monohybrid cross in the F1, the expression of both in the F2 and the proportion of 3:1 obtained at the F2 can be explained by:
1. Law of Dominance
2. Law of segregation
3. Law of Independent Assortment
4. Two-factor interaction
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Which of the following is not an X – linked recessive disorder in humans?
| 1. | Red-green colour blindness |
| 2. | Haemophilia |
| 3. | Duchenne muscular dystrophy |
| 4. | Vitamin D-resistant rickets |
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