The basic structural unit of silicates is-

1.	\( \mathrm{SiO}_4{}^{4-}\)	2.	\(\left(\mathrm{SiO}_3\right)^{2-} \)
3.	\(\mathrm{SiO}_4{ }^{2-} \)	4.	\(\mathrm{SiO}^{-}\)

A compound among the following that is not a monomer for a high molecular mass silicone polymer is-

1. ${\mathrm{Me}}_3\mathrm{SiCl}$

2. ${\mathrm{PhSiCl}}_3$

3. ${\mathrm{MeSiCl}}_3$

4. ${\mathrm{Me}}_2{\mathrm{SiCl}}_2$

An anion that cannot be formed by Boron is -

1. ${\mathrm{BF}}_6^{3-}$

2. ${\mathrm{BH}}_4^{-}$

3. $\mathrm{B}{\left(\mathrm{OH}\right)}_4^{-}$

4. ${\mathrm{BO}}_2^{-}$

A compound among the following that is used in cosmetic surgery is -

Identify the correct statements among the following:

1. (a) and (c) only

2. (b) and (c) only

3. (c) and (d) only

4. (a), (b) and (c) only

Which one of the following reactions does not come under hydrolysis type reaction?

1. ${\mathrm{SiCl}}_{4\left(1\right)}+2{\mathrm{H}}_2{\mathrm{O}}_{\left(1\right)}\to {\mathrm{SiO}}_{2\left(\mathrm{s}\right)}+4{\mathrm{HCl}}_{\left(\mathrm{aq}\right)}$

2. ${\mathrm{Li}}_3{\mathrm{N}}_{\left(\mathrm{s}\right)}+3{\mathrm{H}}_2{\mathrm{O}}_{\left(1\right)}\to {\mathrm{NH}}_{3\left(\mathrm{g}\right)}+3{\mathrm{LiOH}}_{\left(\mathrm{aq}\right)}$

3. $2{\mathrm{F}}_{2\left(\mathrm{g}\right)}+2{\mathrm{H}}_2{\mathrm{O}}_{\left(\mathrm{l}\right)}\to 4{\mathrm{HF}}_{\left(\mathrm{aq}\right)}+{\mathrm{O}}_{2\left(\mathrm{g}\right)}$

4. ${\mathrm{P}}_4{\mathrm{O}}_{10\left(\mathrm{s}\right)}+6{\mathrm{H}}_2{\mathrm{O}}_{\left(1\right)}\to 4{\mathrm{H}}_3{\mathrm{PO}}_{4\left(\mathrm{aq}\right)}$

Why the +1 oxidation state in group 13 and +2 oxidation state in group 14 becomes more and more stable with increasing atomic number?

1. Due to the Inert pair effect

2. Due to a decrease in electronegativity

3. Due to the increase in the size of an atom

4. Due to a decrease in electron affinity

What is the hydrolysis product of AlCl₃ and hybridization of Al in this product?

1. ${\left[\mathrm{Al}{\left({\mathrm{H}}_2\mathrm{O}\right)}_6\right]}^{3+} \& {\mathrm{sp}}^3$

2. ${\left[\mathrm{Al}{\left({\mathrm{H}}_2\mathrm{O}\right)}_6\right]}^{3+} \& {\mathrm{sp}}^3\mathrm{d}$

3. ${\left[\mathrm{Al}{\left({\mathrm{H}}_2\mathrm{O}\right)}_4\right]}^{3+} \& {\mathrm{sp}}^3$

4. ${\left[\mathrm{Al}{\left({\mathrm{H}}_2\mathrm{O}\right)}_6\right]}^{3+} \& {\mathrm{sp}}^3{\mathrm{d}}^2$

The reason behind carbon showing catenation property but lead does not is:

1. Due to the smaller size of C than that of Pb

2. Due to the smaller size of Pb than that of C

3. Due to the smaller ionization energy of C than that of Pb

4. Due to the inert pair effect

Why does the element silicon, not form a graphite-like structure whereas carbon does?

1. Due to the smallest size and highest electronegativity of Si-element in group

2. Due to the smallest size and Highest electronegativity of C-element in group

3. Due to inert pair effect

4. Due to Fajan's rule