- 1(current)
Q. No.Each branch in the following circuit has a resistance \(R\).
The equivalent resistance of the circuit between points \(A\) and \(B\) is:
| 1. | \(R\) | 2. | \(2R\) |
| 3. | \(4R\) | 4. | \(8R\) |
Subtopic: Â Combination of Resistors |
Level 3: 35%-60%
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The current flowing through the resistance \(R_1\), when \(R_1=R_2\) and \(R_3=R_4\) is:
| 1. | \(\frac{V}{4\left(R_1+R_3\right)}\) | 2. | \(\frac{2 V}{\left(R_1+R_3\right)}\) |
| 3. | \(\frac{V}{\left(R_1+R_3\right)}\) | 4. | \(\frac{V}{2\left(R_1+R_3\right)}\) |
Subtopic: Â Combination of Resistors |
 50%
Level 3: 35%-60%
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All the resistances shown in the network are equal to \(1~\Omega.\) Find the resistance of the network measured between \(A\) and \(D.\)
| 1. | \(1~\Omega\) | 2. | \(2~\Omega\) |
| 3. | \(\dfrac{1}{2}~\Omega\) | 4. | \(\dfrac{1}{4}~\Omega\) |
Subtopic: Â Combination of Resistors |
 53%
Level 3: 35%-60%
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Nine similar resistors of resistance \(R\) are connected as shown in the figure. Equivalent resistance between points A and B is:
1. \(\frac{3}{5} R\)
2. \(\frac{4}{3} R\)
3. \(\frac{9}{5} R\)
4. \(R\)
1. \(\frac{3}{5} R\)
2. \(\frac{4}{3} R\)
3. \(\frac{9}{5} R\)
4. \(R\)
Subtopic: Â Combination of Resistors |
Level 3: 35%-60%
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A thin circular conducting wire is connected at \(A,B\) where the smaller arc \(AB\) represents \(\dfrac14^{\text{th}}\) of the circumference. A current flows from \(A\) to \(B,\) dividing into two branches \(i_1\) and \(i_2\) at \(A.\) The ratio \(i_1:i_2\) equals:
| 1. | \(3\) | 2. | \(4\) |
| 3. | \(\dfrac13\) | 4. | \(1\) |
Subtopic: Â Combination of Resistors |
 57%
Level 3: 35%-60%
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