Q. No.A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in the fusion reaction is \(0.02866~\text{u}\). The energy liberated per nucleon is: (given \(1~\mathrm{u} = 931~\text{MeV}\) )
1. \(26.7~\text{MeV}\)
2. \(6.675~\text{MeV}\)
3. \(13.35~\text{MeV}\)
4. \(2.67~\text{MeV}\)
If the nuclear radius of \(^{27}\text{Al}\) is \(3.6\) Fermi, the approximate nuclear radius of \(^{64}\text{Cu}\) in Fermi is:
1. \(2.4\)
2. \(1.2\)
3. \(4.8\)
4. \(3.6\)
The power obtained in a reactor using \(\mathrm{U}^{235}\) disintegration is \(1000~\text{kW}\). The mass decay of \(\mathrm{U}^{235}\) per hour is approximately equal to:
1. \(20~\mu\text{g}\)
2. \(40~\mu\text{g}\)
3. \(1~\mu\text{g}\)
4. \(10~\mu\text{g}\)
| 1. | atoms get ionized at high temperature |
| 2. | kinetic energy is high enough to overcome the Coulomb repulsion between nuclei |
| 3. | molecules break up at high temperature |
| 4. | nuclei break up at high temperature |
A nucleus \({ }_{{n}}^{{m}} {X}\) emits one \(\alpha\text -\text{particle}\) and two \(\beta\text- \text{particle}\) The resulting nucleus is:
1. \(^{m-}{}_n^6 Z \)
2. \(^{m-}{}_{n}^{4} X \)
3. \(^{m-4}_{n-2}Y\)
4. \(^{m-6}_{n-4} Z \)
The mass of a nucleus is \(0.042~\text{u}\) less than the sum of the masses of all its nucleons. The binding energy per nucleon of the nucleus is near:
1. \(4.6~\text{MeV}\)
2. \(5.6~\text{MeV}\)
3. \(3.9~\text{MeV}\)
4. \(23~\text{MeV}\)
\({ }_{\mathrm{Z}}^{\mathrm{A}} \mathrm{X} \rightarrow { }_{\mathrm{Z}+1}^{\mathrm{A}} \mathrm{Y}\rightarrow { }_{\mathrm{Z-1}}^{\mathrm{A-4}} \mathrm{B}\rightarrow { }_{\mathrm{Z-1}}^{\mathrm{A-4}} \mathrm{B}\)
1. \(\beta, \alpha, \gamma\)
2. \( \gamma, \beta, \alpha\)
3. \(\beta, \gamma,\alpha\)
4. \(\alpha,\beta, \gamma\)
The number of beta particles emitted by a radioactive substance is twice the number of alpha particles emitted by it. The resulting daughter is an:
1. Isobar of a parent.
2. Isomer of a parent.
3. Isotone of a parent.
4. Isotope of a parent.
The decay constants of two radioactive materials X1 and X2 are \(5\lambda\) and \(\lambda\) respectively. Initially, they have the same number of nuclei. The ratio of the number of nuclei of X1 to that of X2 will be \(1/e\) after a time:
1. \(\lambda\)
2. \(\frac{1}{2\lambda }\)
3. \(\frac{1}{4\lambda }\)
4. \(\frac{e}{\lambda }\)
If \(M(A,~Z)\), \(M_p\), and \(M_n\) denote the masses of the nucleus \(^{A}_{Z}X,\) proton, and neutron respectively in units of \(u\) (\(1~u=931.5~\text{MeV/c}^2\)) and represent its binding energy \((BE)\) in \(\text{MeV}\). Then:
| 1. | \(M(A, Z) = ZM_p + (A-Z)M_n- \frac{BE}{c^2}\) |
| 2. | \(M(A, Z) = ZM_p + (A-Z)M_n+ BE\) |
| 3. | \(M(A, Z) = ZM_p + (A-Z)M_n- BE\) |
| 4. | \(M(A, Z) = ZM_p + (A-Z)M_n+ \frac{BE}{c^2}\) |
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