Select Chapter Topics:

A hollow conducting sphere of radius \(1~\text{m}\) is given a positive charge of \(10~\mu\text{C}\). The electric field at the centre of the hollow sphere will be:

1. | \(60\times10^{3}~\text{Vm}^{-1}\) | 2. | \(90\times10^{3}~\text{Vm}^{-1}\) |

3. | zero | 4. | infinite |

Subtopic: Â Gauss's Law |

Â 93%

From NCERT

AIPMT - 1998

To view explanation, please take trial in the course.

NEET 2025 - Target Batch

Hints

Links

To view explanation, please take trial in the course.

NEET 2025 - Target Batch

A charge \(q\) is placed in a uniform electric field \(E.\) If it is released, then the kinetic energy of the charge after travelling distance \(y\) will be:

1. | \(qEy\) | 2. | \(2qEy\) |

3. | $\frac{qEy}{2}$ | 4. | $\sqrt{qEy}$ |

Subtopic: Â Electric Field |

Â 76%

From NCERT

AIPMT - 1998

To view explanation, please take trial in the course.

NEET 2025 - Target Batch

Hints

Links

To view explanation, please take trial in the course.

NEET 2025 - Target Batch

The electric field at the equator of a dipole is \(E.\) If the strength of the dipole and distance are now doubled, then the electric field will be:

1. | \(E/2\) | 2. | \(E/8\) |

3. | \(E/4\) | 4. | \(E\) |

Subtopic: Â Electric Dipole |

Â 66%

From NCERT

AIPMT - 1998

To view explanation, please take trial in the course.

NEET 2025 - Target Batch

Hints

Links

To view explanation, please take trial in the course.

NEET 2025 - Target Batch

A point \(Q\) lies on the perpendicular bisector of an electric dipole of dipole moment \(p.\) If the distance of \(Q\) from the dipole is \(r\) (much larger than the size of the dipole), then the electric field at \(Q\) is proportional to:

1. \(p^{2}\) and \(r^{-3}\)

2. \(p\) and \(r^{-2}\)

3. \(p^{-1}\) and \(r^{-2}\)

4. \(p\) and \(r^{-3}\)

Subtopic: Â Electric Dipole |

Â 86%

From NCERT

AIPMT - 1998

To view explanation, please take trial in the course.

NEET 2025 - Target Batch

Hints

Links

To view explanation, please take trial in the course.

NEET 2025 - Target Batch

In Millikan oil drop experiment, a charged drop falls with a terminal velocity \(v\). If an electric field \(E\) is applied vertically upwards it moves with terminal velocity \(2v\) in upward direction. If electric field reduces to \(\frac{E}{2}\) then its terminal velocity will be:

1. \(\frac{v}{2}\)

2. \(v\)

3. \(\frac{3v}{2}\)

4. \(2v\)

Subtopic: Â Electric Field |

From NCERT

AIPMT - 1999

To view explanation, please take trial in the course.

NEET 2025 - Target Batch

Hints

Links

To view explanation, please take trial in the course.

NEET 2025 - Target Batch

The electric field at centre \(O\) of a semicircle of radius \(a\) having linear charge density \(\lambda\) is given by:

1. | \(\dfrac{2\lambda}{\epsilon_0 a}\) | 2. | \(\dfrac{\lambda\pi}{\epsilon_0 a}\) |

3. | \(\dfrac{\lambda}{2\pi \epsilon_0 a}\) | 4. | \(\dfrac{\lambda}{\pi \epsilon_0 a}\) |

Subtopic: Â Electric Field |

Â 82%

From NCERT

AIPMT - 2000

To view explanation, please take trial in the course.

NEET 2025 - Target Batch

Hints

To view explanation, please take trial in the course.

NEET 2025 - Target Batch

If a charge \(Q\) is situated at the corner of a cube, the electric flux passing through all six faces of the cube is:

1. | \(\frac{Q}{6\varepsilon_0}\) | 2. | \(\frac{Q}{8\varepsilon_0}\) |

3. | \(\frac{Q}{\varepsilon_0}\) | 4. | \(\frac{Q}{2\varepsilon_0}\) |

Subtopic: Â Gauss's Law |

Â 67%

From NCERT

AIPMT - 2000

To view explanation, please take trial in the course.

NEET 2025 - Target Batch

Hints

Links

To view explanation, please take trial in the course.

NEET 2025 - Target Batch

Who evaluated the mass of electron indirectly with help of charge:

1. Thomson

2. Millikan

3. Rutherford

4. Newton

Subtopic: Â Electric Charge |

Â 77%

From NCERT

AIPMT - 2000

To view explanation, please take trial in the course.

NEET 2025 - Target Batch

Hints

Links

To view explanation, please take trial in the course.

NEET 2025 - Target Batch

If a charge \(Q~\mu\text{C}\) is placed at the centre of the cube, the flux (In SI unit) coming out from any surface will be:

1. | \(\dfrac{Q}{6\varepsilon_0}\times10^{-6}\) | 2. | \(\dfrac{Q}{6\varepsilon_0}\times10^{-3}\) |

3. | \(\dfrac{Q}{2\varepsilon_0}\) | 4. | \(\dfrac{Q}{8\varepsilon_0}\) |

Subtopic: Â Gauss's Law |

Â 86%

From NCERT

AIPMT - 2001

To view explanation, please take trial in the course.

NEET 2025 - Target Batch

Hints

Links

To view explanation, please take trial in the course.

NEET 2025 - Target Batch

A dipole of moment \(\vec p\) is placed in uniform electric field \(\vec E\). The torque acting on it is given by:

1. \(\vec{\tau }=\vec{p}\cdot \vec{E}\)

2. \(\vec{\tau }=\vec{p} \times \vec{E}\)

3. \(\vec{\tau }=\vec{p}+ \vec{E}\)

4. \(\vec{\tau }=\vec{p}- \vec{E} \)

Subtopic: Â Electric Dipole |

Â 90%

From NCERT

AIPMT - 2001

To view explanation, please take trial in the course.

NEET 2025 - Target Batch

Hints

Links

To view explanation, please take trial in the course.

NEET 2025 - Target Batch

Select Chapter Topics: