A particle is executing a simple harmonic motion. Its maximum acceleration is $\alpha$ and maximum velocity is $\beta$. Then its time period of vibration will be:

When two displacements are represented by $y_1 = a \text{sin}(\omega t)$ and $y_2 = b\text{cos}(\omega t)$ are superimposed, then the motion is:

A particle is executing SHM along a straight line. Its velocities at distances $x_1$ and $x_2$ from the mean position are $v_1$ and $v_2$, respectively. Its time period is:

The oscillation of a body on a smooth horizontal surface is represented by the equation, $X=A \text{cos}(\omega t)$,
where $X=$ displacement at time $t,$ $\omega=$ frequency of oscillation.
Which one of the following graphs correctly shows the variation of acceleration, $a$ with time, $t?$
($T=$ time period)

1.		2.
3.		4.

A particle of mass $m$ is released from rest and follows a parabolic path as shown. Assuming that the displacement of the mass from the origin is small, which graph correctly depicts the position of the particle as a function of time?
           

1.		2.
3.		4.

The displacement of a particle along the x-axis is given by, x = asin²$\mathrm{\omega }$t. The motion of the particle corresponds to: