1. | \(\Delta Q=\Delta U+\Delta W\) |
2. | \(\Delta U=\Delta Q+\Delta W\) |
3. | \(\Delta U=\Delta Q-\Delta W\) |
4. | \(\Delta U+\Delta Q+\Delta W=0\) |
1. | work done by the system is \(120\) J. |
2. | work done on the system is \(120\) J. |
3. | work done by the system is \(80\) J. |
4. | work done on the system is \(80\) J. |
If an average person jogs, he produces \(14.5 \times10^3\) cal/min. This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming \(1\) kg requires \(580 \times10^3\) cal for evaporation) is:
1. | \(0.25\) kg | 2. | \(0.50\) kg |
3. | \(0.025\) kg | 4. | \(0.20\) kg |
\(1\) g of water of volume \(1\) cm3 at \(100^\circ \text{C}\) is converted into steam at the same temperature under normal atmospheric pressure \(\approx 1\times10^{5} \) Pa. The volume of steam formed equals \(1671\) cm3. If the specific latent heat of vaporization of water is \(2256\) J/g, the change in internal energy is:
1. \(2423\) J
2. \(2089\) J
3. \(167\) J
4. \(2256\) J
The first law of thermodynamics is a statement of:
1. | conservation of heat |
2. | conservation of work |
3. | conservation of momentum |
4. | conservation of energy |
Consider the process on a system shown in the figure. During the process, the work done by the system:
1. | continuously increases |
2. | continuously decreases |
3. | first increases then decreases |
4. | first decreases then increases |
An ideal gas goes from the state \(i\) to the state \(f\) as shown in figure given below. The work done by the gas during the process,
1. | is positive |
2. | is negative |
3. | is zero |
4. | cannot be obtained from this information |
The molar specific heat at a constant pressure of an ideal gas is \(\dfrac{7}{2}R.\) The ratio of specific heat at constant pressure to that at constant volume is:
1. | \(\dfrac{7}{5}\) | 2. | \(\dfrac{8}{7}\) |
3. | \(\dfrac{5}{7}\) | 4. | \(\dfrac{9}{7}\) |