A heat engine operates between the temperatures of 300 K and 500 K. If it extracts 1200 J of heat energy from the source, then the maximum amount of work that can be done by the engine is:

1. 720 J

2. 520 J

3. 480 J

4. 200 J

Subtopic:  Carnot Engine |
 82%
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If 3 moles of a monoatomic gas do 150 J of work when it expands isobarically, then a change in its internal energy will be:

1. 100 J 2. 225 J
3. 400 J 4. 450 J
Subtopic:  Molar Specific Heat |
 77%
From NCERT
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In the case of free expansion, when a sample of gas expands suddenly, the change in internal energy of the gas will be:

1. Positive

2. Negative

3. Zero

4. May be positive or negative

Subtopic:  First Law of Thermodynamics |
 61%
From NCERT
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The work done for the given process AB is:

   

1. 6P0V0

2. 5P0V0

3. 3P0V0

4. 2P0V0

Subtopic:  Work Done by a Gas |
 52%
From NCERT
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The efficiency of a Carnot heat engine working between the temperatures \(27^{\circ}\mathrm{C}\) and \(227^{\circ}\mathrm{C}\) is:
1. 0.1
2. 0.6
3. 0.2
4. 0.4

Subtopic:  Carnot Engine |
 81%
From NCERT
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Work done during the given cycle is:
                               
1. 4P0V0

2. 2P0V0

3. 12P0V0

4. P0V0

Subtopic:  Work Done by a Gas |
 78%
From NCERT
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The cyclic process of 2 moles of diatomic gas is shown in the figure. Which of the following statements is correct?

    

1.  Process BC is an isothermal compression.
2.  Work done in the process CA is \(4 R T_0\)
3.  Work done in the process AB is zero.
4.  All of these

Subtopic:  Cyclic Process |
From NCERT
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An ideal gas is enclosed in an insulated cylinder. The piston is frictionless and attached to an ideal spring. When the gas is heated, then:
           

1. the work is done against the spring only.
2. the work is done against the atmospheric pressure only.
3. the internal energy of gas increases.
4. the work is equal to the heat supplied.

Subtopic:  First Law of Thermodynamics |
 59%
From NCERT
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If a gas undergoes the change in its thermodynamic state from A to B via two different paths, as shown in the given pressure (P) versus volume (V) graph, then:

1. the temperature of the gas decreases in path 1 from A to B.
2. the heat absorbed by the gas in path 1 is greater than in path 2.
3. the heat absorbed by the gas in path 2 is greater than in path 1.
4. the change in internal energy in path 1 is greater than in path 2.

Subtopic:  First Law of Thermodynamics |
 76%
From NCERT
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The PV diagram of an ideal gas is shown in the figure. The work done by the gas in the process 1234 is given by:

          

1. \(\frac{9}{2}P_0V_0\)
2. \(\frac{15}{2}P_0V_0\)
3. \(\frac{13}{2}P_0V_0\)
4.  \(\frac{3}{2}P_0V_0\)

 

Subtopic:  Work Done by a Gas |
 52%
From NCERT
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