A cup of coffee cools from \(90^{\circ}\mathrm{C}\) to \(80~^{\circ}\mathrm{C}\) in t minutes, when the room temperature is \(20^{\circ}\mathrm{C}\). The time taken by a similar cup of coffee to cool from \(80^{\circ}\mathrm{C}\) to \(60^{\circ}\mathrm{C}\) at room temperature same at \(20^{\circ}\mathrm{C}\) is:
1. \(\frac{10}{13}t\) 
2. \(\frac{5}{13}t\)
3. \(\frac{13}{10}t\)
4. \(\frac{13}{5}t\)

Subtopic:  Newton's Law of Cooling |
 62%
From NCERT
NEET - 2021
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NEET 2023 - Target Batch - Aryan Raj Singh
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An object kept in a large room having an air temperature of \(25^\circ \text{C}\) takes \(12\) minutes to cool from \(80^\circ \text{C}\) to \(70^\circ \text{C}.\) The time taken to cool for the same object from \(70^\circ \text{C}\) to \(60^\circ \text{C}\) would be nearly:
1. \(10\) min
2. \(12\) min
3. \(20\) min
4. \(15\) min

Subtopic:  Newton's Law of Cooling |
 78%
From NCERT
NEET - 2019
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NEET 2023 - Target Batch - Aryan Raj Singh
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To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh