Q. No.Select the correct option based on statements below:
| Assertion (A): | of aniline is higher than ethylamine. |
| Reason (R): | The lone pair of group in aniline is involved in conjugation with a benzene ring. |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | Both (A) and (R) are false. |
Select the correct option based on statements below:
| Assertion (A): | Only a small amount of HCI is required in the reduction of nitro compounds with iron scrap and HCI in the presence of steam. |
| Reason (R): | FeCl2 formed gets hydrolyzed to release HCI during the reaction. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | Both (A) and (R) are False. |
The correct statement regarding the basicity of arylamines is:
| 1. | Arylamines are generally more basic than alkylamines because the lone-pair electrons of nitrogen are not delocalized by interaction with the aromatic ring π-electron system. |
| 2. | Arylamines are generally more basic than alkylamines because of the aryl group +I effect. |
| 3. | Arylamines are generally more basic than alkylamines because the nitrogen atom in arylamines is sp-hybridized. |
| 4. | Arylamines are generally less basic than alkylamines because the nitrogen lone-pair electrons are delocalized by interaction with the aromatic ring π-electron system. |
Which of the following compounds, when reduced with lithium aluminium hydride, produces a secondary amine?
1. Nitroethane
2. Methylisocyanide
3. Acetamide
4. Methyl cyanide
A compound "A", when reacted with PCl5 and then with ammonia, gives "B". "B" on treatment with bromine and caustic potash produces "C". "C" on treatment with NaNO2 and HCl at C and then boiling produces ortho-cresol. Compound "A" is:
1. o-Toluic acid
2. o-Chlorotoluene
3. o-Bromotoluene
4. m-Toluic acid
In a set of reactions, propanoic acid yielded a compound (D).
\(CH_3CH_2COOH\ \text{(A)} \xrightarrow[]{SOCl_2}\ \text{(B)} \)
\(\ \xrightarrow[]{NH_3}\ \text{(C)}\ \xrightarrow[Br_2]{KOH}\ \text{(D)}\)
The formula for (D) is:
1.
2.
3.
4.
Mark the correct increasing order of basic strength of given molecules:
 |
 |
 |
| (I) | (II) | (III) |
1. III < I < II
2. III < II < I
3. II < I < III
4. II < III < I
CH3CH2CO-NH2 can be converted into CH3CH2NH2 in the presence of:
1. LiAlH4
2. H2/Pt
3. Sn/HCl
4. NaOBr/OH–
1. CH3NH2 > (CH3)2NH > (CH3)3N
2. (CH3)2NH > CH3NH2 > (CH3)3N
3. (CH3)3N > CH3NH2 > (CH3)2NH
4. (CH3)3N > CH3NH2 > (CH3)2NH
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