The mass of a non-volatile solute (molar mass 40 g mol–1) that should be dissolved in 114 g octane
to reduce its vapour pressure to 80 % would be-

1. 6 g

2. 7 g

3. 8 g

4. 10 g

Subtopic:  Relative Lowering of Vapour Pressure | Raoult's Law |
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Benzene and toluene form an ideal solution over the entire range of composition. The vapour pressure of pure benzene and toluene at 300 K are 50.71 mm Hg and 32.06 mm Hg respectively.

The mole fraction of benzene in vapour phase, if 80 g of benzene is mixed with 100 g of toluene, would be -

1. 0.41

2. 0.68

3. 0.72

4. 0.59

Subtopic:  Relative Lowering of Vapour Pressure | Raoult's Law |
From NCERT
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The vapour pressure of 1 molal solution of a non-volatile solute in water at 300 K would be -

(The vapour pressure of water at 300 K = 12.3 kPa)

1. 21.08 kPa 2. 12.08 kPa
3. 33.08 kPa 4. 4.08 kPa
Subtopic:  Relative Lowering of Vapour Pressure |
 74%
From NCERT
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