Two elements A and B form compounds having formula AB2 and AB4. When dissolved in 20 g of benzene (C6H6), 1 g of AB2 lowers the freezing point by 2.3 K whereas 1.0 g of AB4 lowers it by 1.3 K. The atomic masses of A and B are respectively -

(Kf for benzene is 5.1 K kg mol-1)

1. 15.59 u and 52.64 u

2. 25.59 u and 42.64 u

3. 13.59 u and 52.64 u

4. 23.59 u and 32.64 u

Subtopic:  Depression of Freezing Point |
 60%
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The type of inter molecular interactions present in

(a) n-hexane and n-octane (i) Van der Waal’s forces of attraction
(b) NaClO4 and water (ii) ion-dipole interaction
(iii) dipole-dipole interaction
 
(a) (b)
1. (i) (ii)
2. (ii) (ii)
3. (i) (iii)
4. (iii) (iii)
Subtopic:  Azeotrope |
 63%
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The insoluble compound in water is /are

1. Phenol

2. Formic acid and toluene

3. Phenol and toluene 

4. Toluene and chloroform

Subtopic:  Introduction & Colligative properties |
 59%
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If the solubility product of CuS is 6 × 10–16, the maximum molarity of CuS in an aqueous solution will be

1. 1.45 × 10−8 mol L−1 2. 3.45 × 10−8 mol L−1
3. 2.45 × 10−8 mol L−1 4. 4.25 × 10−8 mol L−1
Subtopic:  Concentration Terms & Henry's Law |
 66%
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The mass percentage of aspirin (C9H8O4) in acetonitrile (CH3CN) when 6.5 g of C9H8O4 is dissolved in 450 g of CH3CN will be:

1. 1.424% 2. 4.424%
3. 5.124% 4. 2.124%
Subtopic:  Concentration Terms & Henry's Law |
 83%
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Nalorphene (C19H21NO3), similar to morphine, is used to combat withdrawal symptoms in narcotic users. The dose of nalorphene generally given is 1.5 mg.

Calculate the mass of 1.5 × 10−3m aqueous solution required for the above dose.

1. 13.22 g 2. 3.22 g
3. 11.22 g 4. 9.22 g
Subtopic:  Concentration Terms & Henry's Law |
 75%
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The amount of benzoic acid (C6H5COOH) required for preparing 250 mL of 0.15 M solution in methanol is -

1. 4.57 g 2. 3.57 g
3. 1.57 g 4. 12.57 g
Subtopic:  Concentration Terms & Henry's Law |
 78%
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The depression in the freezing point of water when 10 g of CH3CH2CHClCOOH is added to 250 g of water will be -

 (Ka = 1.4 × 10–3, Kf = 1.86 K kg mol-1)

1. 0.32 K

2. 2.87 K

3. 0.65 K

4. 5.03 K

Subtopic:  Depression of Freezing Point |
 62%
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19.5 g of CH2FCOOH is dissolved in 500 g of water. The van’t Hoff factor and dissociation constant of fluoroacetic acid will be respectively -

(Tf = 1.00 K )

1) 20.75 , 4.77 x 10-3

2) 1.075 ,  4.77 x 10-2

3) 2.073 , 3.07 x 10-4

4) 1.075 , 3.07 x 10-3

Subtopic:  Van’t Hoff Factor |
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Henry’s law constant for the solution of methane in benzene at 298 K is 4.27 × 105 mm Hg. The mole fraction of methane in benzene at 298 K under 760 mm Hg will be:

1. 1.85 × 105

2. 192 × 104

3. 178 × 105

4. 18.7 × 10–5

Subtopic:  Concentration Terms & Henry's Law |
 73%
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