The correct option for the number of body centred unit cells in all 14 types of Bravais lattice unit cells is :

1. 2

2. 3

3. 7

4. 5

An element has a body-centered cubic (BCC) structure with a cell edge of 288 pm. The atomic radius is:

1. $\frac{\sqrt{2}}{4}\times 288$ pm

2. $\frac{4}{\sqrt{3}}\times 288$ pm

3. $\frac{4}{\sqrt{2}}\times 288$ pm

4. $\frac{\sqrt{3}}{4}\times 288$ pm

If a is the length of the side of a cube, the distance between the body-centered atom and one corner atom in the cube will be:

1. $\frac{2}{\sqrt{3}}a$

2. $\frac{4}{\sqrt{3}}a$

3. $\frac{\sqrt{3}}{4}a$

4. $\frac{\sqrt{3}}{2}a$

The number of carbon atoms per unit cell of a diamond is:

1. 8

2. 6

3. 1

4. 4

Lithium metal crystallizes in a body-centered cubic crystal. If the length of the side of the unit cell of lithium is 351 pm, the atomic radius of the lithium will be:

1. 240.8 pm

2. 151.8 pm

3. 75.5 pm

4. 300.5 pm

For a cubic crystal structure, which one of the following relations indicating the cell characteristic is correct?

1. $a\ne b\ne c$ $and$ $\alpha \ne \beta$ $and$ $\gamma \ne 90°$

2. $a\ne b\ne c$ $and$ $\alpha =\beta$ $=$ $\gamma =90°$

3. $a=b=c$ $and$ $\alpha \ne \beta$ $=$ $\gamma =90°$

4. $a=b=c$ $and$ $\alpha =\beta =$ $\gamma =90°$

CsBr crystallises in a body-centered cubic lattice. The unit cell length is 436.6 pm. Given that the atomic mass of Cs = 133 amu and that of Br = 80 amu and the Avogadro number being 6.02×10²³ mol^-1, the density of CsBr is:

1. 42.5 $g/c{m}^3$

2. 0.425 $g/c{m}^3$

3. 8.25 $g/c{m}^3$

4. 4.25 $g/c{m}^3$

The number of atoms per unit cell in a BCC structure is:

1. 9

2. 4

3. 2

4. 1

The cations and anions are arranged in an alternate form in:

1. Metallic crystal

2. Ionic crystal

3. Co-valent crystal

4. Semi-conductor crystal

A cube of a crystal has an A-atom placed at every corner and B-atom placed at every centre of face. The formula of the compound is:

1. AB

2. AB₃

3. A₂B₂

4. A₂B₃