The similarity between metallic and ionic crystals is -

1. Both these crystal types are held by the electrostatic force of attraction.
2. Both these crystal types are held by the Van der Waal's forces of attraction.
3. Both these crystal types are held by  hydrogen bonding.
4. Both these crystal types are held by covalent bonding.

Subtopic:  Introduction & Crystal System |
 73%
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A cubic solid is made of two elements P and Q. Atoms of Q occupy the corners of the cube and P occupy the body centre. The formula of this compound and the coordination number of Q are respectively - 

1. PQ, 8

2. P2Q, 8

3. P2Q2, 8

4. PQ, 12

Subtopic:  Voids, Radius Ratio & Coordination Number |
 76%
From NCERT
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Niobium crystallizes in body-centred cubic structure. If the density is 8.55 g cm−3, the atomic radius of niobium (atomic mass 93 u) is -

1. 13.32 nm

2. 12.32 nm

3. 14.32 nm

4. 15.32 nm

Subtopic:  Density & Packing Fraction |
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If the radius of the octahedral void is r and the radius of the atoms in close packing is R, the relation between r and R would be -

1. r = 0.114R

2. r = 0.444R

3. r = 1.414R

4. r = 0.414R

Subtopic:  Voids, Radius Ratio & Coordination Number |
 66%
From NCERT
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Higher conductivity of p-type and n-type semiconductors is due to:

1. Increase in the number of positive holes and mobile electrons respectively.
2. Increase in the number of electrons in both types of semiconductors.
3. Increase in the number of positive-holes in both types of semiconductors.
4. None of the above.
Subtopic:  Imperfections in Solids & Semiconductors |
 82%
From NCERT
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(i) Ge is doped with In

(ii) Si is doped with B. 

The semiconductors formed in the above cases are :

1. (i) n-type semiconductor  (ii) p-type semiconductor .

2. (i) p-type semiconductor  (ii) n-type semiconductor .

3. p-type semiconductor in both the cases.

4. n-type semiconductor in both the cases.

Subtopic:  Imperfections in Solids & Semiconductors |
 66%
From NCERT
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Aluminum crystallizes in a cubic close-packed structure. It's metallic radius is 125 pm. The number of unit cells in 1.00 cm3 of aluminum are : 

1. 2.27 x 1022

2. 354 x 1022

3. 4.54 x 1022

4. 127 x 1020

Subtopic:  Introduction & Crystal System |
From NCERT
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NaCl is doped with 10−3 mol % of SrCl2. The number of cation vacancies post doping would be -

1. 4.022 × 108

2. 5.022 × 1018

3. 6.022 × 1018

4. 7.022 × 108

Subtopic:  Imperfections in Solids & Semiconductors |
 85%
From NCERT
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The relation between the atomic mass of unknown metal with density and the dimension of its unit cell is given by  :

(Given: All the cell edge lengths are equal)

1. \(m \ = \ \frac{\rho a^{3}N_{A}}{Z} \)
2. \(m \ = \ \rho a^{3}N_{A}Z\)
3. \(m \ = \ \frac{Z}{\rho a^{3}N_{A}}\)
4. \(m \ = \ \frac{ZN_{A}}{a^{3}\rho}\)

Subtopic:  Density & Packing Fraction |
 84%
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The correct statement among the following is -

1. Semiconductors have a small energy gap between the valence band and the conduction band.
2. Conductors have overlapped valence band and conduction band.
3. Insulators have a large energy gap between the valence band and conduction band.
4. All of the above.

Subtopic:  Imperfections in Solids & Semiconductors |
 92%
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