The compound that has the maximum melting point among the following is-

1. ${\mathrm{C}}_4{\mathrm{H}}_{10}$ $$ $$                                 

2. ${\mathrm{C}}_5{\mathrm{H}}_{12}$

3. ${\mathrm{C}}_6{\mathrm{H}}_{14}$ $$                                  

4. ${\mathrm{C}}_7{\mathrm{H}}_{16}$

The compound most likely to decolorise a solution of cold basic ${\mathrm{KMnO}}_4$ is: 

1. CH₃– CH₃                                              

2.  CH₃CH₂CH₃

3. $({\mathrm{CH}}_3{)}_4\mathrm{C}$                                                   

4. ${\mathrm{CH}}_3\mathrm{CH}$ $=$ ${\mathrm{CHCH}}_2{\mathrm{CH}}_2{\mathrm{CH}}_3$

The compound  among the following that undergoes reaction with ammonical ${\mathrm{AgNO}}_3$ is-

1. 

2. $C{H}_3 – CH = CH – C \equiv CH$

3. $C{H}_3– C{H}_{2}CH = CH – C{H}_2 – C{H}_3$

4. $C{H}_2 = CH – C{H}_2– C{H}_3$

The correct order of acidity among the following is:

 ${\mathrm{CH}}_3\mathrm{Cl} \& {\mathrm{C}}_2{\mathrm{H}}_5\mathrm{Cl}$ undergoes Wurtz reaction to give-

The number of isomeric sodium salt of acid that will be required to obtain neopentane is-

1. 3                                   

2. 1

3. 4                                                  

4. 6

$\stackrel{\stackrel{\mathrm{H}}{|}}{\mathrm{C}}{\mathrm{H}}_2-\stackrel{\stackrel{\mathrm{Cl}}{|}}{\mathrm{C}}{\mathrm{H}}_2\underset{\mathrm{alc}.}{\overset{\mathrm{NaOH}}{\to }}{\mathrm{CH}}_2={\mathrm{CH}}_2$

The most probable mechanism for the above reaction is-

1. E1                                        

2. E2

3. $E$ $1_{CB}$                                    

4. $\mathrm{\alpha -}$elimination

The compound that will react most readily with gaseous bromine has the formula:

Hydrocarbon (A) reacts with bromine by substitution reaction to form an alkyl bromide B.
B undergoes the Wurtz reaction to give a gaseous hydrocarbon containing less than four carbon atoms.

The formula of (A) is:

1. $\mathrm{CH}\equiv \mathrm{CH}$
2. ${\mathrm{CH}}_2={\mathrm{CH}}_2$ 
3. ${\mathrm{CH}}_3-{\mathrm{CH}}_3$
4. ${\mathrm{CH}}_4$

The compound ${\mathrm{C}}_7{\mathrm{H}}_8$ undergoes the following reactions

${\mathrm{C}}_7{\mathrm{H}}_8\stackrel{3{\mathrm{Cl}}_2/\mathrm{hv}}{\to }\mathrm{A}\stackrel{{\mathrm{Br}}_2/\mathrm{Fe}}{\to }\mathrm{B}\stackrel{\mathrm{Zn}/\mathrm{HCl}}{\to }$ C

The product 'C' is-

1. m–Bromotoluene

2. o–Bromotoluene

3. 3–Bromo–2,4,6–trichlorotoluene

4. p–Bromotoluene