n-Butylbenzene on oxidation with hot alkaline KMnO₄ gives:

1.	Benzoic acid	2.	Butanoic acid
3.	Benzyl alcohol	4.	Benzaldehyde

The compound among the following that undergoes bromination of its aromatic ring

(electrophilic aromatic substitution) at the fastest rate is-

1.		2.
3.		4.

Consider the following sequence of reactions.

${\mathrm{C}}_6{\mathrm{H}}_6$ $+$ ${\mathrm{CH}}_3\mathrm{CH}={\mathrm{CH}}_2\underset{\mathrm{heat}}{\overset{{\mathrm{H}}_3{\mathrm{PO}}_4}{\to }}\mathrm{A}\underset{2.{\mathrm{H}}_3{\mathrm{O}}^{+},}{\overset{}{\to }}$ $\mathrm{heat}1.{\mathrm{O}}_2,\mathrm{Heat}\mathrm{B}+\mathrm{C}$

The products (B) and (C) are respectively-

1. Benzaldehyde, and acetaldehyde

2. Benzoic acid, and acetic acid

3. Phenol, and propionaldehyde

4. Phenol, and acetone

In the above compound, Cl will liberate easily in the form of-

1. ${\mathrm{Cl}}^{\oplus }$

2. Cl^-

3. Cl

4. Cl²⁺

(A) C₈H₁₀ $\stackrel{{\mathrm{KMnO}}_4}{\to }$ (B)  C₈H₆O₄$\underset{\mathrm{Fe}}{\overset{{\mathrm{Br}}_2}{\to }}$  C₈H₅BrO₄  (C)  (one-product only)

The structure of A in the above-mentioned reaction is-

1.		2.
3.		4.

The product (B) in the above-mentioned reaction is-

1.		2.
3.		4.

Cyclopentadiene is much more acidic than cyclopentane, beacuse -

1. Cyclopentadiene has conjugated double bonds.

2. Cyclopentadiene has both sp² and sp³ hybridized carbon atoms.

3. Cyclopentadiene is a strain-free cyclic system.

4. Cyclopentadienyl anion ion, the conjugate base of cyclopentadiene, is an aromatic species and hence has higher stability.

 The compounds among the following that can be generated by Friedel craft acylation is/are -

I.
II.
III.
IV.

     
The product B in the above mentioned reaction is -

1.		2.
3.		4.

The major product obtained in the given reaction is:

1.		2.
3.		4.